Answer:
Use the distance formula on both points AC and AB.
<em>Distance formula is this</em><em>:</em>
<em>\begin{gathered}d=\sqrt{(x2-x1)^2+(y2-y1)^2} \\\\d=\sqrt{(1--5)^2+(8--7)^2} \\\\d=\sqrt{(6)^2+(15)^2} \\\\d=\sqrt{36+225} \\\\d=\sqrt{261} \\\\\end{gathered}d=(x2−x1)2+(y2−y1)2d=(1−−5)2+(8−−7)2d=(6)2+(15)2d=36+225d=261</em>
Distance for AC is 16.16
Now do the same with the numbers for AB and get the distance of 5.39
2. To get the area, use the formula 1/2 x base x height
AB is the base and AC is the height.
1/2 x 16.16 x 5.39 = 43.55
the answer is 43.5
Answer: 7n
Step-by-step explanation:
Because....
First Remove the parentheses (a) = a
= 11n - 3n - n
Then add similar elements: 11n - 3n - n = 7n
= 7n
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~ 234483279c20~
Answer:
(0,2)
Step-by-step explanation:
solve by addition/elimination
2x + 3y= 6
–3x + 5y = 10
multiply first equation by 3 and second one by 2 to eliminate x)
6x+9y=18
-6x+10y=20 (add the two equations)
6x+9y-6x+10y=38
19y=38
y=38/19=2
2x+3y=6
2x=6-6
x=0
1 week = 7 days
1 gallon = 16 cups ⇒ 1 cup = 1/16 gallon
1.5 cups = 1.5 · 1/16 gallon = 15 · 1/160 gallon = 3/32 gallon
1.5 cups per day = 3/32 gallons per day = 7 · 3/32 gallons per week
= 21/32 gallons per week
The length and width of rectangular traffic sign are 40 and 30 inches respectively
<h3><u>Solution:</u></h3>
Given that,
Perimeter of rectangular traffic sign = 140 inches
Let length and width be denoted as ‘L’ and ‘B’ respectively
Given that length is 10 inches longer than its width
L = 10 + B
<em><u>The perimeter of rectangle is given as:</u></em>
Perimeter = 2( L + B)
On substituting the values, we get
140 = 2(10 + B + B)
140 = 2(10 + 2B)
140 = 20 + 4B
B = 30
Therefore, the length is L = 10 + 30 = 40
Hence the dimensions length and width of the rectangle are 40 and 30 inches respectively.
