Where do comparison using<,> to show the relationship between |-2/3| and -5/6

Mathematics

1 answer:

Dmitrij [34]3 years ago

4 0

-5/6 <-2/3 would be your answer

hope this helps

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Find a quadratic model for the set of values: (-2, -20), (0, -4), (4, -20). Show your work.

Ivahew [28]

Ok... so this question can be solved by using simultaneous equations.

Use the general from of a parabola

$y = ax^2 + bx + c$

you know the value of c, the y-intercept... y = -4

which means the equation is

$y = ax^2 + bx - 4$

now use the other 2 points to get 2 equations in 2 unknowns

(-2, -20) just substitute

$-20 = (-2)^2a + (-2)b - 4 ~~~or~~~ -20 = 4a - 2b - 4$

this becomes

$4a - 2b = -16$

now the other equation using (4, -20)

The simplified form is

6 0

3 years ago

Which could be the first step in simplifying this expression (x^3x^-6)^2

exis [7]

If you follow PEMDAS
P-parentheses
E-exponent
M-multiplication
D-divide
a-addition
s-subtraction
then you should look in the parentheses and multiplying 3x should be your first step IF you know x
hope this helps :)

5 0

3 years ago

Read 2 more answers

The cash drawer of the market contains $227. There are six more $5 bills than $10 bills. The number of $1 bills is two more than

k0ka [10]

Answer:

There are 122 one dollar bills, 11 five dollar bills and 5 ten dollar bills.

Step-by-step explanation:

There are bills of one dollar, five dollars and ten dollars on the cash drawer, therefore the sum of all of them multiplied by their respective values must be equal to the total amount of money on the drawer. We will call the number of one dollar bills, five dollar bills and ten dollar bills, respectively "x","y" and "z", therefore we can create the following expression:

$x + 5*y + 10*z = 227$

We know that there are six more 5 dollar bills than 10 dollar bills and that the number of 1 dollar bills is two more than 24 times the number of 10 dollar bills, therefore:

$y = z + 6\\x = 2 + 24*z$