Question

A welder must cut a piece of metal so that it fits tightly into its spot. The welder cuts 9/16 of an inch off the metal so that it measures 3 3/4 inches. What was the size of the original piece of metal?

Answer 1

Answer: $4\dfrac{5}{16}\text{ inches}$

Step-by-step explanation:

Given : A welder must cut a piece of metal so that it fits tightly into its spot.

The size of the metal which he cut off= $\dfrac{9}{16}\text{ inch}$

The new size of the metal after he cut off a piece = $3\dfrac{3}{4}\text{ inch}$

$=\dfrac{15}{4}\text{ inches}$

Now, the size of the original piece of metal :-

$\dfrac{9}{16}+\dfrac{15}{4}\text{ inches}\\\\=\dfrac{9+15(4)}{16}\text{ inches}\\\\=\dfrac{69}{16}\text{ inches}=4\dfrac{5}{16}\text{ inches}$

Hence, the size of the original piece of metal was $4\dfrac{5}{16}\text{ inches}$

Answer 2

. A welder must cut a piece of metal so that it fits tightly into its spot. The welder cuts 5/16 of an inch off the metal so that it measures 3 3/4 inches. What was the size of the original piece of metal?  

c 4 1/16