Answer:
Height of the Pyramid = 3.125 m
The surface area of the pyramid is 635.5 sq. meters
Step-by-step explanation:
Here, the length and width of the rectangle = 16 m and 14 m
Let the height of the pyramid = h m
Volume of the pyramid = 700 cubic meters
Volume of Rectangular Pyramid = Length x Width x Height
or, 700 = 16 x 14 x h
or, [tex]h = \frac{700}{14 \times 16} = 3.125[/t)ex]
or, the Height of the Pyramid = 3.125 m
Now, the Surface area of Rectangular Pyramid = 2( LW + WH + HL)
Here, Surface Area = 2 ( (16 x 14 ) + (14 x 3.125) + (3.125 x 16))
= 2( 224 + 43.75 + 50) = 2 x 317.75
or, Surface Area = 635.5 sq. meters
Hence, the surface area of the pyramid is 635.5 sq. meters
