3 years ago

How many moles are present in 4.51x1015 atoms of Aluminum (Al)?

1 answer:

8 0

Answer:

divide by avagadro number to get the amount of moles in the atoms you have

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kap26 [50]

[( 91 * 10^-1 ) *10^ -5]^-4 = (91 * 10^-6)^-4 = 91^-4 * 10^24 = ( 10^24 )/ ( 91^4 ) =
10000000 ≈ 1458258211769

7 0

3 years ago

attashe74 [19]

Answer:

The atomic mass

Step-by-step explanation:

The decimal at the bottom of an element represents how much one atom of that element weighs.

5 0

3 years ago

Sergio [31]

Jack had b boxes. Then he got 4 more. That is equal to:

$b+4$

On Wednesday, half the boxes were destroyed. To find half the amount, you can divide by 2, which is equal to:

$\frac{b+4}{2}$

Choice C matches the answer. Your answer is C

5 0

3 years ago

andrezito [222]

Answer:

the correct answer would be 6 inches.

Step-by-step explanation:

12*.5=6

7 0

3 years ago

Papessa [141]

Answer:

x=-7

Step-by-step explanation:

divide 12 on both sides and that equals -7

8 0

3 years ago