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AURORKA [14]
3 years ago
5

A formula for finding A, the area of a triangle is A=1/2bh, where b is the base of the triangle and h is the altitude to that ba

se. In this triangle, if b=16 inches, and h=6 inches, what is the area of this triangle?
Mathematics
1 answer:
seropon [69]3 years ago
7 0

Answer:

48 inches²

Step-by-step explanation:

Substitute b = 16 and h = 6 into the formula for A

A = \frac{1}{2} × 16 × 6 = 8 × 6 = 48 inches²


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Set A contains three different positive odd integers and two different positive even integers; set B contains two different posi
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Answer:

\frac{2}{5}*\frac{3}{5} +\frac{2}{5}*\frac{2}{5}+\frac{3}{5} *\frac{3}{5}  = \frac{19}{25}

Step-by-step explanation:

We must remember that in order to get one even number we need to multiply one even number times one odd number or two even numbers. So, the first term tells the probability of having an even number from A and an even number from B, the next would be even from A and odd from B and the last one tells the likelihood of having odd from A and even from B

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72kg in a ratio of 1:3:5
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first of all you add all of the ratios together so it would be 1+3+5 That equals 9 then divide 72 by 9 which gets you 8. Then you times 8 by all of the ratios to get the answer 8:24:40
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The equation of a circle is (x+2)2 + (y-3)2 =9. What are the coordinates of the center of this circle?
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center is (-2,3)

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2 years ago
Quadrilateral ABCD is translated 2 units left and 3 units up to form quadrilateral A'B'C'D'
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The answer would be
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3 years ago
Construct a 98% confidence interval to determine whether there is any difference between the mean drug concentration in tablets
inna [77]

Answer:

Step-by-step explanation:

So, we are given two sites;

Site one: 91.28 , 92.83, 89.35, 91.90 82.85, 94.83, 89.83, 89.00, 84.62, 86.96, 88.32, 91.17, 83.86, 89.74, 92.24, 92.59, 84.21, 89.36, 90.96, 92.85, 89.39, 89.82, 89.91, 92.16, 88.67.

=> The mean = add up all the numbers/ the total numbers (which is 25). = 89.55.

=> The standard deviation = 3.005

SITE TWO: 89.35 86.51 89.04 91.82 93.02 88.32 88.76 89.26 90.36 87.16 91.74 86.12 92.10 83.33 87.61 88.20 92.78 86.35 93.84 91.20 93.44 86.77 83.77 93.19 81.79.

=> The mean= add up all the numbers/ the total numbers (which is 25). = 89.033.

=> Standard deviation = 3.271.

NB: the assumption here is that the variance for both sites are the same.

STEP ONE: DETERMINE THE DEGREE OF FREEDOM AND THE CRITICAL VALUE.

The degree of freedom =( mean of site 1 ) + (mean of site 2) - 2 = (25 + 25) − 2 = 48.

Since the degree of freedom is 48, Recall that the value for alpha given = 0.02. Then, the critical value = 2.407.

STEP TWO: DETERMINE THE STANDARD DEVIATION AND THE STANDARD ERROR FOR BOTH.

Therefore, the standard deviation = √[( 25 - 1) × 3.005^2 + (25 -1) × 3.271^2) ÷ (25 +25 - 2) ] = 3.14.

Also, the standard error = standard deviation × ( √(1/ mean 1 + 1/mean 2) ..

Standard error = 3.14 × [ ✓( 1/25 + 1/25)] = 0.89.

STEP THREE: DETERMINE THE CONFIDENCE INTERVAL.

confidence interval = (89.548 - 89.033 - 2.41 × 0.89, 89.548 - 89.033 + 2.41 × 0.89) = (- 1.62, 2.65).

STEP FOUR: THE HYPOTHESES.

=> THE TWO TAILED TEST.

Jo:μ1​ = μ2​.

Ja: μ1​ ≠ μ2​.

Thus, the rejected region is {t : ∣ t ∣ > 2.7}

As critical value = 2.7 for the degree of freedom which is 48 and α=0.01.

If we do the t - test for this,.we will have;

(89.548 - 89.003)÷ ( standard deviation × √ ( 1/25 + 1/25). = 0.58.

So,from our t - value, is less or equals to the critical value, therefore, the null hypothesis is not rejected.

Also, from the p-value table which gives p=0.565. The p- value is greater than or equal to the alpha value(0.01). therefore, the null hypothesis is not rejected.

We are not going to reject the null hypothesis because the information gathered is not enough.

3 0
2 years ago
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