Okay, so in order to find how much she earns per hour you'll take the salary she earns each week ($198.60) and divide that to how many hours she works every week (15 hours). It'll look like: 198.60 / 15= $13.24 per hour.
Answer:
15 mph
Step-by-step explanation
i used a calculator but correct me if im wrong pls
Answer:
The inequality tha can be used to find how many more bags of popcorn Jeff still needs to sell today to make a profit is
x - 12 ≥ 40.
Step-by-step explanation:
Let us represent the number of bags of popcorn as p
Jeff sells popcorn for $3 per bag. To make a profit each day, he needs to sell at least $120 worth of popcorn.
We have the equation:
$3 × p ≥ $120
3p ≥ $120
p ≥ 120/3
p ≥ 40 bags
He must sell at least 40 bags to make a profit
He has sold $36 worth of popcorn today.
1 bag is $3
Hence, he has sold
$36/$3 = 12 bags of popcorn
Which inequality can be used to find Jeff still needs to sell today to make a profit?
This equality is given as:
x - 12 bags ≥ 40 bags
x - 12 ≥ 40
x ≥40 - 12
x ≥ 28 bags
She still need to sell 28 more bags of popcorn.
Answer:
-Exponential Decay
-Decay factor is (1-0.05)
Step-by-step explanation:
-Given that the number decreases by a defined rate each year from the initial size by 5%,
-This is an exponential decay function of the form:
![y=Ae^{-rt}](https://tex.z-dn.net/?f=y%3DAe%5E%7B-rt%7D)
Where:
is the quantity/size after time t
is the initial size
is the rate of decay
-Our function can the be written as
![y=45000e^{-0.05t}](https://tex.z-dn.net/?f=y%3D45000e%5E%7B-0.05t%7D)
Hence, the decay rate/factor is 0.05
#Alternatively
The exponential decay can be of the form:
![y=ab^x](https://tex.z-dn.net/?f=y%3Dab%5Ex)
Where:
y is the size at time x, a is the initial size, x is time and b is the decay factor.
b is of the form ![b=(1-r),\ \ r=decay\ rate](https://tex.z-dn.net/?f=b%3D%281-r%29%2C%5C%20%5C%20%20r%3Ddecay%5C%20%20rate)
![y=ab^x\\\\y=45000(1-0.05)^x](https://tex.z-dn.net/?f=y%3Dab%5Ex%5C%5C%5C%5Cy%3D45000%281-0.05%29%5Ex)
Hence, the decay factor is (1-0.05)
Answer:
720
Step-by-step explanation:
hope it helps