All categories

3 years ago

Area of a rectangle is 36 what is x if the width is x and length is x+5

Mathematics

1 answer:

Reika [66]3 years ago

5 0

If the length is x+5, the width would be x(x+5)=36

You might be interested in

Let g be the function given by g(x)=x^2*e^(kx) , where k is a constant. For what value of k does g have a critical point at x=2/

ArbitrLikvidat [17]

G `( x ) = $2x * e^{kx} + k x^{2} *e^{kx} = \\ = xe^{kx}(2 + kx )$
2 + k x = 0
k x = -2
k = -2: x = - 2 : 2/3 = - 2 * 3/2
k = - 3
Answer: for k= - 3, the function g ( x ) have a critical point at x = 2/3.

8 0

3 years ago

Find the 10th term of the sequence 1,10,19,28,...

Rainbow [258]

For the first one the nth term is 9n - 8 so the 10th term is 9x10 - 8 = 90-8 = 82

For the second one the nth term is ⅓n + ⅓ so the 11th term is ⅓x11 +⅓ = 3.9999 = 4

5 0

4 years ago

The line of best fit for a scatter plot is shown:

scoray [572]

(0,6)(4,3)
slope = (3 - 6) / (4 - 0) = -3/4
ur y int (where the line crosses the y axis) is (0,6)

in y = mx + b form, the slope will be in the m position and the y int will be in the b position.

Therefore, ur equation is : y = -3/4x + 6 <==

8 0

3 years ago

Read 2 more answers

Q3.

Bas_tet [7]

1-560 WOULD BE THW ANSWER IM SORRY THIS IS

8 0

3 years ago

Find the x intercepts of the parabola with vertex (4,75) and y intercept (0,27)

user100 [1]

The equation for a parabola with vertex $(h, k)$ is
$y=a(x-h)^{2}+k$

We plug in:
$y=a(x-4)^{2}+75$

We find $a$ by plugging in the point $(0, 27)$ :
$27=a(0-4)^{2}+75$
$\Rightarrow 27=a(-4)^{2}+75$
$\Rightarrow 27=16a+75$
$\Rightarrow 16a=-48$
$\Rightarrow a=-3$

So our equation is
$y=-3(x-4)^{2}+75$

To find x-intercepts, we set $y=0$ :
$-3(x-4)^{2}+75=0$
$\Rightarrow -3(x-4)^{2}=-75$
$\Rightarrow (x-4)^{2}=25$
$\Rightarrow x-4=5, -5$
$\Rightarrow x=9, -1$

So the x-intercepts are 9 and -1.

8 0

3 years ago