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MrMuchimi
3 years ago
11

ΔABC is dilated by a scale factor of 0.25 with the origin as the center of dilation, resulting in the image ΔA′B′C′. If A = (-1,

-5), B = (2, 1), and C = (14, 17 ), what is the length of B'C'?
Mathematics
1 answer:
Leni [432]3 years ago
8 0

Answer:

5

Step-by-step explanation:

To find B and C prime, you must multiply them by .25, or 1/4.


B' =  

(-2 x .25),(1 x .25)


I did mine in fraction form, because it will prove to be more useful in future mathematics.


B' = (1/2  ,  1/4)


Repeat the process with C.


C' =

(14 x .25),(17 x .25)


C' =

(7/2  ,  17/4)




You only need to focus on B and C because you are finding the length of B'C'.


The formula for distance is the square root of x to the sub of 2 minus x to the sub of 1 squared minus y to the sub of 2 minus y to the sub of 1 square.


x2 -  x1 =  7/2  -  1/2  =  6/2  =  3 squared  =  9


y2 - y1 = 17/4 - 1/4 = 16/4  =  4 squared = 16


16 + 9  = 25


Square root of 25 is 5.


Therefore, the distance is 5.


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From the given information:

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Number of term N = 3 (0.5)^{5} + 3 (0.5)^{6} + 3 (0.5)^{7} +3 (0.5)^{8}+3 (0.5)^{9} +3 (0.5)^{10} +3 (0.5)^{11}+3 (0.5)^{12}+ 3 (0.5)^{13}

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