4 years ago

What are the solutions to the equation √x2+2x-10=√x+20

1 answer:

5 0

√x^2+2x-10=√x+20
raising both members to the square
 x^2+2x-10=x+20
rewriting
x^2+x-30=0
factoring
(x+6)(x-5)=0
therefore the solutions are
 x = –6, x = 5
the answer is
B. x = –6, x = 5

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