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nikdorinn [45]
3 years ago
14

ANSWER ASAP!!!!! Evaluate ƒ(x) = |3x – 2| for ƒ(–5) and ƒ(7). Question 7 options: A) ƒ(–5) = 8, ƒ(7) = 7 B) ƒ(–5) = 12, ƒ(7) = –

2 C) ƒ(–5) = –17, ƒ(7) = 9 D) ƒ(–5) = 17, ƒ(7) = 19
Mathematics
1 answer:
saul85 [17]3 years ago
7 0

Answers:

  • f(-5) = 17
  • f(7) = 19

====================================

Work Shown:

Plug in x = -5. Use PEMDAS to simplify

f(x) = |3x-2|

f(-5) = |3(-5)-2| ... replace every x with -5

f(-5) = |-15-2|

f(-5) = |-17|

f(-5) = 17

---------------------

Repeat for x = 7

f(x) = |3x-2|

f(7) = |3*7-2| ... replace every x with 7

f(7) = |21-2|

f(7) = |19|

f(7) = 19

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<h3>Given:</h3><h3>Large cone:</h3>
  • r= 8 cm
  • h= 20 cm
<h3>Small cone:</h3>
  • r= 4 cm
  • h= 10cm
<h3>Note that:</h3>
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  • h: height
<h3>To find:</h3>
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<h3>Solution:</h3>
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\large\boxed{Formula: V= \frac{1}{3}\pi{r}^{2}h}

Let's solve!

First, let's find the volume of the smaller cone.

Substitute the values according to the

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V= \frac{1}{3}×\pi×{4}^{2}×10

V= 167.5516082 \: {cm}^{3}

Now, we can round off to the nearest hundredth.

The value in the thousandths place is smaller than 5 so we won't have to round up.

\boxed{V= 167.55 \: {cm}^{3}}

Next, let's find the volume of the bigger cone.

Substitute the values according to the formula.

V= \frac{1}{3}×\pi×{8}^{2}×20

V= 1340.412866 \: {cm}^{3}

Now, we can round off to the nearest hundredth.

The value in thousandths place is smaller than 5 so we won't have to round up.

\boxed{V=1340.41 \: {cm}^{3}}

Now, we can find the volume of the frustum.

We'll have to minus the volume of the smaller cone from the bigger cone.

V= 1340.41-167.55

\large\boxed{V= 1172.86 \: {cm}^{3}}

<u>Hence, the volume of the frustum is 1172.86 cubic centimeters.</u>



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