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Kaylis [27]
2 years ago
10

What is the sum of the next to next two numbers in his sequence:1,4,9,16,25,___ ___ ?​

Mathematics
2 answers:
k0ka [10]2 years ago
5 0

Answer:

41, 66

Step-by-step explanation:

16+ 25 = 41

41 + 25 = 66

Hatshy [7]2 years ago
4 0

Answer:

85

Step-by-step explanation:

the pattern is adding by odd numbers increasing in value

so 1+3 =4,  4+5=9,  9+7=16,  16+9=25,  25+11=36,  36+13=49

36+49 = 85

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three friends decide to rent an apartment for a total of 972 per month if they share the rent equally, which of the following op
Bumek [7]

972 / 3 = $324

Which means that each person will pay $324

8 0
3 years ago
Angles S and T are corresponding
g100num [7]
6x = 3x + 12 so 3x = 12 then x = 4
6 0
2 years ago
The sum of two consecutive even integers is 106. what are the integers
jolli1 [7]
Let the consecutive even integers be x and (x+2).

x + (x + 2) = 106

2x + 2 = 106

2x = 104

x = 52

Thus the two integers are 52 and 54.




7 0
2 years ago
What is the least common multiple (LCM) of 3 and 4?
Alexxx [7]

Answer:Least common multiple (LCM) of 3 and 4 is 12. Least common multiple or lowest common denominator (lcd) can be calculated in two way; with the LCM formula calculation of greatest common factor (GCF), or multiplying the prime factors with the highest exponent factor. Least Common Multiple of 3 and 4 with GCF Formula.

Step-by-step explanation:

6 0
3 years ago
A certain restaurant offers 8 different salads, 5 different main courses, 6 different desserts. If customers choose one salad, o
Naddika [18.5K]

Answer: E. 1200

Step-by-step explanation:

Given : A certain restaurant offers 8 different salads, 5 different main courses, 6 different desserts.

i.e. No. of choices for different salads= 8  -----(1)

No. of choices for different main courses = 5  ----(2)

No. of choices for different desserts = 6

When we choose two different desserts then we use permutation(repeatition not allowed) :

^6P_2=\dfrac{6!}{(6-2)!}=\dfrac{6\times5\times4!}{4!}=6\times5=30----(3)

[∵ No. of ways to choose r things out of n =^nP_r=\dfrac{n!}{(n-r)!} ]

If customers choose one salad, one main course and two different desserts for their meal , then By Fundamental principle of counting (Multiply (1) , (2) and (3)), the number of  different meals are possible :-

8\times5\times30\\\\=1200

Hence, the correct answer is E. 1200 .

8 0
3 years ago
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