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zavuch27 [327]
3 years ago
9

PLEASE HELP! what's the answer for this?

Mathematics
1 answer:
Verizon [17]3 years ago
7 0
A cube with side length 1 unit is called a unit cube
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-9 - (18v - 5) = 2(7v - 16) - 3v​
andrezito [222]

Answer:

v = 28/29

Step-by-step explanation:

- 9 - (18v - 5) = 2(7v - 16) - 3v​

- 9 - 18v + 5 = 14v - 32 - 3v

- 18v - 14v + 3v = - 32 - 5 + 9

- 29v = - 28

v = -28 / -29

v = 28/29

6 0
3 years ago
Find the equivalent exponential expression.<br> (4^2)4
steposvetlana [31]

Answer:

4^8

Step-by-step explanation:

If the second 4 is an exponent, as in (4^2)^4, then multiply the exponents.

(4^2)^4 = 4^(2 * 4) = 4^8

3 0
3 years ago
Which graph represents a function with an initial value of 1/2
melisa1 [442]
<span>The initial value is the value of the y-coordinate when the x-coordinate is equal to 0. That is the same to say the value at which the graph intercepts the y-axis. So, you justt have to pick the graph whose line intercepts the y-axis at 1/2. </span>
8 0
3 years ago
Read 2 more answers
The angle of depression from the top of a cruise ship to the top of a sailboat is 22. Sitting above water, the cruise ship is 23
dusya [7]

Answer:

The distance between the cruise ship and the sail boat is 517 feet.

Step-by-step explanation:

The cruise ship is 236 feet tall, and the sailboat is 236 tall; this means the distance between the top of the cruise ship and the top of the sail boat is

236 feet - 27 feet = 209 feet.

We also know that the angel of depression from the top of the cruise ship to the bottom of the cruise ship is 22°. This forms a right triangle as shown in the figure attached.

Now from trigonometry we get:

tan \: \theta = \dfrac{209}{d}

d= \dfrac{209}{tan\:\theta }

\boxed{d=517ft}

The distance between the cruise ship and the sailboat is 517 feet.

3 0
3 years ago
Help me please,Thanks
Alborosie

the formula for volume of a prism is base x height
4 0
3 years ago
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