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3 years ago

Solve for x. Enter the solutions from least to greatest.

Mathematics

1 answer:

worty [1.4K]3 years ago

8 0

Answer:

less than 7, greater than 1

Step-by-step explanation:

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Solve x^2-8x-9=0 algebrically

SVETLANKA909090 [29]

Answer:

X = 9, -1

Step-by-step explanation:

1, Factor it

(x-9) (x+1) = 0

2. Both of a factor will = 0

x-9 = 0

x+1=0

3. Solve

x=9

x=1

7 0

3 years ago

6 ft. 12 ft. 8 ft. The area of this irregular figure is -sq. ft. 16 ft.

nikdorinn [45]

Answer:

When we know all 3 sides, we use Heron's Formula

area = sqrt [s *(s-a) * (s-b) * (s-c)]

where "s" is the semi-perimeter which in this case equals

s = (6 + 8 + 12) / 2 = 13

area = sqrt [13 * 5 * 7 * 1]

area = sqrt 455

area = 21.3307290077

area = 21.33 square feet (rounded)

Step-by-step explanation:

3 0

3 years ago

A(n) ________ is both equilateral and equiangular?

bekas [8.4K]

I believe it was a rectangle I'm not sure test it out.

8 0

3 years ago

Read 2 more answers

Which is bigger, one-fifth of 35 or two-sixths of 24?

GREYUIT [131]

Answer:

two-sixths of 24

Step-by-step explanation:

7<8

5 0

3 years ago

a silo is shaped like a cylinderwith a cone on top. the radii of the bases of the cylinder and cone are both equal to 8 feet. th

Ymorist [56]

Answer:

5430.85 square feet

Step-by-step explanation:

Height of the cylindrical part of the cilo = 25 feet

radius of the base cylindrical part of cilo = 8 feet

Now volume of cylindrical part of cilo = $\pi r^{2} h$

Volume of cylindrical part of cilo = $\pi(8^{2})25$ = $1600\pi square feet$

Now,

Height of the conical part of cilo = 6 feet

Radius of the conical part of cilo = 8 feet

Volume of the conical part of cilo = $\frac{1}{3}\pi (8^{2})6$ = $128\pi square feet$

Volume of the entire cilo = $1600\pi + 128\pi = 1728\pi$

since $\pi =\frac{22}{7} therefore,$

volume of entire cilo = $\frac{22}{7} (1728)$ = 5430.85

3 0

3 years ago