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r-ruslan [8.4K]
4 years ago
10

Problem:

Mathematics
1 answer:
Lana71 [14]4 years ago
4 0

Answer:

B is all about addition and multiplication

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In this equation, is (1, 5) a solution? *
monitta

Answer:

No (1,5) is not a solution

Step-by-step explanation:

if you try to solve this equation with the (1,5), you lay it out like 5 = 1/4 * 1 - 7. It turns into  5 = 1/4 - 7, because 1 times anything is that same number. Then you have to add 7 to both sides so that it cancels out on the right and you get 12 on the left. So you end up with the equation 12 = 1/4. This equation is not true, so therefore (1,5) is not a solution. Hope this helps :)

8 0
3 years ago
The eatery restaurant has 200 tables a recent evening there were reservations for 1/10 of the tables how many tables were reserv
leonid [27]
1. 20 tables are reserved.

2. I know this because...
   - If I make an equivalent fraction to 1/10, using 200 as the denominator, I get:
       · 1/10 x 20 = 20/200 tables are reserved.

Hope this helped! :)
5 0
3 years ago
Read 2 more answers
Henry is making a corn grits recipe that calls for 1/4 cup of corn grits every 1/2 cup of water.how much water will he need if h
Mariana [72]
3 cups I think not sure hope this has helpful and I am sorry if it wasn’t have a good dat
5 0
3 years ago
NO LINKS!! Please help me with these notes. Part 1a​
erik [133]

Answers:

When we evaluate a logarithm, we are finding the exponent, or <u>    power   </u>  x, that the  <u>   base   </u> b, needs to be raised so that it equals the <u>  argument   </u> m. The power is also known as the exponent.

5^2 = 25 \to \log_5(25) = 2

The value of b must be <u>   positive    </u> and not equal to <u>   1   </u>

The value of m must be <u>   positive   </u>

If 0 < m < 1, then x < 0

A <u>   logarithmic  </u>    <u>   equation  </u> is an equation with a variable that includes one or more logarithms.

===============================================

Explanation:

Logarithms, or log for short, basically undo what exponents do.

When going from 5^2 = 25 to \log_5(25) = 2, we have isolated the exponent.

More generally, we have b^x = m turn into \log_b(m) = x

When using the change of base formula, notice how

\log_b(m) = \frac{\log(m)}{\log(b)}

If b = 1, then log(b) = log(1) = 0, meaning we have a division by zero error. So this is why b \ne 1

We need b > 0 as well because the domain of y = log(x) is the set of positive real numbers. So this is why m > 0 also.

5 0
3 years ago
I was absent for this so yeah
Tju [1.3M]
The answer NOT simplified is 14 over 18 but SIMPLIFIED it would equal 7 over 9
5 0
3 years ago
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