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2 years ago

Please help!!! will mark brainliest

Mathematics

2 answers:

faust18 [17]2 years ago

6 0

Your answer is 7.

I subtracted 5 from 12 to find the missing number for KL that is 7.

Therefore, your answer is 7

3241004551 [841]2 years ago

6 0

Answer:

I think so it is negative 7

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In a multiple choice quiz there are 5 questions and 4 choices for each question (a, b, c, d). Robin has not studied for the quiz

Ahat [919]

Answer:

a) There is a 18.75% probability that the first question that she gets right is the second question.

b) There is a 65.92% probability that she gets exactly 1 or exactly 2 questions right.

c) There is a 10.35% probability that she gets the majority of the questions right.

Step-by-step explanation:

Each question can have two outcomes. Either it is right, or it is wrong. So, for b) and c), we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

In this problem we have that:

Each question has 4 choices. So for each question, Robin has a $\frac{1}{4} = 0.25$ probability of getting ir right. So $\pi = 0.25$ . There are five questions, so $n = 5$ .

(a) What is the probability that the first question she gets right is the second question?

There is a 75% probability of getting the first question wrong and there is a 25% probability of getting the second question right. These probabilities are independent.

$P = 0.75(0.25) = 0.1875$

There is a 18.75% probability that the first question that she gets right is the second question.

(b) What is the probability that she gets exactly 1 or exactly 2 questions right?

This is: $P = P(X = 1) + P(X = 2)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 1) = C_{5,1}.(0.25)^{1}.(0.75)^{4} = 0.3955$

$P(X = 2) = C_{5,2}.(0.25)^{2}.(0.75)^{3} = 0.2637$

$P = P(X = 1) + P(X = 2) = 0.3955 + 0.2637 = 0.6592$

There is a 65.92% probability that she gets exactly 1 or exactly 2 questions right.

(c) What is the probability that she gets the majority of the questions right?

That is the probability that she gets 3, 4 or 5 questions right.

$P = P(X = 3) + P(X = 4) + P(X = 5)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 3) = C_{5,3}.(0.25)^{3}.(0.75)^{2} = 0.0879$

$P(X = 4) = C_{5,4}.(0.25)^{4}.(0.75)^{1} = 0.0146$

$P(X = 5) = C_{5,5}.(0.25)^{5}.(0.75)^{0} = 0.001$

$P = P(X = 3) + P(X = 4) + P(X = 5) = 0.0879 + 0.0146 + 0.001 = 0.1035$

There is a 10.35% probability that she gets the majority of the questions right.

6 0

3 years ago

If x= 6 is the only x-intercept of the graph of a quadratic equation, which statement best describes the discriminant of the

denpristay [2]

Answer:

discriminant is zero (0)

Step-by-step explanation:

Actually, you have a double root here: {6, 6}: "two real, equal roots." That tells us immediately that the value of the discriminant was zero (0).

3 0

3 years ago

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Consider the function represented by the equation 6c = 2p – 10. Write the equation in function notation, where c is the independ

zhuklara [117]

we have

$6c = 2p - 10$

If c is the independent variable

then

p is the dependent variable

clear variable p

$6c = 2p - 10$

Divide by $2$ both sides

$3c = p - 5$

Adds $5$ both sides

$3c+5 = p - 5 +5$

$p=3c+5$

Write the equation in function notation

$f(c)=3c+5$

therefore

the answer is

the equation in function notation is equal to $f(c)=3c+5$

5 0

3 years ago

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After 7 years, Abner earned $1575 in simple interest from a CD into which he initially deposited $6000. What was the annual inte

Radda [10]

The answer is C. 3.75%

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3 years ago

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Jakes truck can tow a max weight of 5,000 pounds. What is the max number of horses he can take in his trailer at one time withou

Gre4nikov [31]

Answer:

He can take 5 Horses at max in his trailer at one time without going over the max weight his truck can tow. (Assuming the average weight of one horse to be equal to 1000 pounds)

Step-by-step explanation:

The no. of horses that can be carried by the truck can be found by simply dividing the maximum weight, that the truck can tow by the weight of a horse.

Max. No of Horses = (Max weight truck can tow)/(Average weight of one horse)

The weight of a horse is not given in the question .Thus, we assume the average weight of one horse, to be equal to 1000 pounds, we get:

Max. No of Horses = 5000 pounds/ 1000 pounds

<u>Max. No of Horses = 5</u>

7 0

3 years ago