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Ede4ka [16]
3 years ago
13

A swimming pool can be filled in 18 hours if water enters through a pipe​ alone, or in 25 hours if water enters through a hose a

lone. If water is entering through both the pipe and the​ hose, how long will it take to fill the pool
5/6 ​full?
Mathematics
1 answer:
pychu [463]3 years ago
6 0
I am not sure, but this is what I got:
 <span>Pipe ALONE = 18 hours 

Pipe ALONE in 1 hour = 1/18 of the pool 

Hose ALONE in 1 hour = 1/25 of the pool 

TOGETHER in 1 HOUR = 1/18 +1/25 = 43/450 

TOGETHER they will fill the pool in 450/43 hours 

So 5/6 of the pool will take 5/6 X 450/43 = 2250/ 258 = 8.7209302 hours OR 

8 hours AND 43.26 minutes ANSWER
</span>
Hope this helps!


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Answer:

\purple{ \bold{ \therefore \: A_{base} = {x}^{2}  + 4x +  16}}

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3 years ago
An electrical engineer wishes to compare the mean lifetimes of two types of transistors in an application involving high-tempera
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(115.2642, 222.7358).

Step-by-step explanation:

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type A: n_1=60, xbar_1=1827, s_1=168

type B: n_2=180, xbar_2=1658, s_2=225

n_1 = sample size 1, n_2= sample size 2

xbar_1, xbar_2 are mean life of sample 1 and 2 respectively. Similarly, s_1 and s_2 are standard deviation of 1,2.

a=0.05, |Z(0.025)|=1.96 (from the  standard normal table)

So 95% CI is

(xbar_1 -xbar_2) ± Z×√[s1^2/n1 + s2^2/n2]

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The snowfall data for Resort A have an interquartile range of around 50. The snowfall data for Resort B have an interquartile ra
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Just did this on edg. :)

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Johnathan ran 5 days this week. The most he ran in one day was 3.5 miles. Write an inequality that shows the distance johnathan
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<em><u>An inequality that shows the distance Johnathan could of ran any day this week is:</u></em>

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The most he ran in 1 day = 3.5 miles

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If we let y be the total distance he can travel in a week then, we may express it as,

y\leq 17.5

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3 years ago
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