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NeTakaya
3 years ago
11

Your grandfather gave you $1.65 with

Mathematics
2 answers:
Lelu [443]3 years ago
5 0

Answer:

$1.98

Step-by-step explanation:

1.65/5=0.33

1.65+0.33=1.98

check: 1.98/6 =0.33

0.33x5=1.65

Alex3 years ago
3 0

Answer:

$1.98

Step-by-step explanation:

1.65 is 1.65/1 in a fraction, then you have to divide 1.65/1 by 5/6.

1.65/1 divide by 5/6

1.65 x 6= 9.9

1 x 5= 5

9.9/5

=1.98

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Answer:

If the question states that they are not being replaced, then the answer is 1/8

If the question states that they are being replaced, then the answer is 1/9

Step-by-step explanation:

3/9 x 2/8 = 1/8

3/9 x 2/9 = 1/9

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8 0
3 years ago
A car is being driven at a rate of 40 ft/sec when the brakes are applied. The car decelerates at a constant rate of 10 ft/sec2.
IRISSAK [1]

Answer:

80 feet

Step-by-step explanation:

Given:

Initial speed of the car (v_0) = 40 ft/sec

Deceleration of the car (\frac{dv}{dt}) = -10 ft/sec²

Final speed of the car (v_x) = 0 ft/sec

Let the distance traveled by the car be 'x' at any time 't'. Let 'v' be the velocity at any time 't'.

Now, deceleration means rate of decrease of velocity.

So, \frac{dv}{dt}=-10\ ft/sec^2

Negative sign means the velocity is decreasing with time.

Now, \frac{dv}{dt}=\frac{dv}{dx}(\frac{dx}{dt}) using chain rule of differentiation. Therefore,

\frac{dv}{dx}\cdot\frac{dx}{dt}= -10\\\\But\ \frac{dx}{dt}=v.\ So,\\\\v\frac{dv}{dx}=-10\\\\vdv=-10dx

Integrating both sides under the limit 40 to 0 for 'v' and 0 to 'x' for 'x'. This gives,

\int\limits^0_{40} {v} \, dv=\int\limits^x_0 {-10} \, dx\\\\\left [ \frac{v^2}{2} \right ]_{40}^{0}=-10x\\\\-10x=\frac{0}{2}-\frac{1600}{2}\\\\10x=800\\\\x=\frac{800}{10}=80\ ft

Therefore, the car travels a distance of 80 feet before stopping.

4 0
3 years ago
Can someone answer number 12 for me
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Answer:

Number 12

Step-by-step explanation:

Number 12 :))

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