To solve this polynomial equation, we first factor the left side.
To factor x² + 8x + 12 = 0, look for factors of 12 that add to 8.
These factors are 6 and 2 so we have (x + 6)(x + 2) = 0.
So either x + 6 = 0 or x + 2 = 0 and solving for
x in each equation, our answer is {-6, -2}.
Answer:
Part A
6/40 = 0.15
Part B
16/40 = 0.4
Part C
10/40 = 0.25
Part D
8/40 = 0.20
Part E
The relative frequency of drawing a five-dollar bill is higher than the other relative frequencies. So, I can predict that Pablo is most likely to have more five-dollar bills than any of the others.
Part F
The relative frequency of drawing a one-dollar bill is lower than the other relative frequencies. So, I can predict that Pablo is most likely to have fewer one-dollar bills than bills of any other denomination.
Part G
It would not be a surprise if Pablo had fewer twenties than ones. The experiment was conducted only 40 times, and the numbers of times one-, ten-, and twenty-dollar bills were drawn are not very far apart. So, the number of twenties could be more or less than the number of ones. The same goes for tens and ones.
If you're on Plato an on slide 20 this Answer is for you:
<em>If Pablo does an experiment 100 times, will the relative frequency be more accurate or less accurate than if he did the experiment 40 times? Why?</em>
Answer: As the number of trials increases, the relative frequency becomes closer to the probability of the event. So, the relative frequency would be more accurate if the experiment were repeated 100 times rather than 40 times.
Answer:68-35
Step-by-step explanation:
Answer:
(a) 0.01029 (b) 4.167 customers (c) 0.4167 hours or 25 minutes (d) 0.5 hours or 30 minutes
Step-by-step explanation:
With an arrival time of 6 minutes, λ=10 clients/hour.
With a service time of 5 minutes per transaction, μ=12 transactions/hour.
(a) The probability of 3 or fewer customers arriving in one hour is
P(C<=3)=P(1)+P(2)+P(3)


(b) The average number of customers waiting at any point in time (Lq) can be calculated as

(c) The average time waiting in the system (Wq) can be calculated as

(d) The average time in the system (W), waiting and service, can be calculated as

The answer is D, 8$. One easy way to do it is to take 10% of 40, which is 4, and double it.