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Juliette [100K]
4 years ago
7

Staph the inequality and plot a point in the solution set. Explain how you know the point is a solution.

Mathematics
1 answer:
seropon [69]4 years ago
8 0

Answer:

The points when graphed are: (3,0) and (0,-5)

Step-by-step explanation:

I know that these points are a solution to the graph because it has one x value and one y value that stays constant.

For an example, if we used an X and Y table we could see that each variable has one other variable.

This is how it look like when graphed:

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Which of the following is the solution set of x2 + 8x + 12 = 0?<br> (-2.-6<br> 2.6
algol [13]

To solve this polynomial equation, we first factor the left side.

To factor x² + 8x + 12 = 0, look for factors of 12 that add to 8.

These factors are 6 and 2 so we have (x + 6)(x + 2) = 0.

So either x + 6 = 0 or x + 2 = 0 and solving for

x in each equation, our answer is {-6, -2}.

6 0
3 years ago
In this activity, you will predict the probability of an event from the relative frequency of the event. Pablo has some one-, fi
Vadim26 [7]

Answer:

Part A

6/40 = 0.15

Part B

16/40 = 0.4

Part C

10/40 = 0.25

Part D

8/40 = 0.20

Part E

The relative frequency of drawing a five-dollar bill is higher than the other relative frequencies. So, I can predict that Pablo is most likely to have more five-dollar bills than any of the others.

Part F

The relative frequency of drawing a one-dollar bill is lower than the other relative frequencies. So, I can predict that Pablo is most likely to have fewer one-dollar bills than bills of any other denomination.

Part G

It would not be a surprise if Pablo had fewer twenties than ones. The experiment was conducted only 40 times, and the numbers of times one-, ten-, and twenty-dollar bills were drawn are not very far apart. So, the number of twenties could be more or less than the number of ones. The same goes for tens and ones.

If you're on Plato an on slide 20 this Answer is for you:

<em>If Pablo does an experiment 100 times, will the relative frequency be more accurate or less accurate than if he did the experiment 40 times? Why?</em>

Answer: As the number of trials increases, the relative frequency becomes closer to the probability of the event. So, the relative frequency would be more accurate if the experiment were repeated 100 times rather than 40 times.

4 0
3 years ago
Which graph shows the solution to the following inequality?
LenaWriter [7]

Answer:68-35

Step-by-step explanation:

8 0
3 years ago
Customers arrive at a bank drive-up window every 6 minutes based on a Poisson distribution. Once they arrive at the teller, serv
Jet001 [13]

Answer:

(a) 0.01029 (b) 4.167 customers (c) 0.4167 hours or 25 minutes (d) 0.5 hours or 30 minutes

Step-by-step explanation:

With an arrival time of 6 minutes, λ=10 clients/hour.

With a service time of 5 minutes per transaction, μ=12 transactions/hour.

(a) The probability of 3 or fewer customers arriving in one hour is

P(C<=3)=P(1)+P(2)+P(3)

P(X)=\lambda^{X}*e^{-\lambda}  /X!

P(1)=10^{1}*e^{-10}  /1!=0.00045\\P(3)=10^{3}*e^{-10}  /3!=0,00227\\P(2)=10^{2}*e^{-10}  /2!=0,00757\\P(x\leq3)=0.00045+0.00227+0.00757 = 0.01029

(b) The average number of customers waiting at any point in time (Lq) can be calculated as

L_{q}=p*L=\frac{\lambda}{\mu}*\frac{\lambda}{\mu-\lambda}\\L_{q}=\frac{10}{12}*\frac{10}{12-10}\\\\L_{q}=100/24=4.167

(c) The average time waiting in the system (Wq) can be calculated as

W_{q}=p*W=\frac{\lambda}{\mu}*\frac{1}{\mu-\lambda}\\W_{q}=(10/12)*(1/(12-10))\\W_{q}=(10/24)=0.4167

(d) The average time in the system (W), waiting and service, can be calculated as

W=\frac{1}{\mu-\lambda}\\W=\frac{1}{12-10}=0.5

6 0
3 years ago
Angela is buying a dress that is on sale for 20% off. If the original price of the dress is $40.00, how much money is Angela sav
neonofarm [45]
The answer is D, 8$. One easy way to do it is to take 10% of 40, which is 4, and double it.
8 0
4 years ago
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