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Juliette [100K]
3 years ago
7

Staph the inequality and plot a point in the solution set. Explain how you know the point is a solution.

Mathematics
1 answer:
seropon [69]3 years ago
8 0

Answer:

The points when graphed are: (3,0) and (0,-5)

Step-by-step explanation:

I know that these points are a solution to the graph because it has one x value and one y value that stays constant.

For an example, if we used an X and Y table we could see that each variable has one other variable.

This is how it look like when graphed:

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H(t)=480t-16t^2<br><br> solve for t <br><br> PLEASE SHOW WORK
Andru [333]

Answer:

x = √30 or -√30

Step-by-step explanation:

480 - 16x^2 = 0

divide both sides by 16

30 - x^2 = 0

-x^2 + 30 = 0

-x^2 = -30

X^2 = 30

x = ± √30

x = √30 or -√30

7 0
3 years ago
Determine the slope of the line. Please explain the answer . If you hurry I’ll mark brainliest
Daniel [21]

Answer:

2/4

Step-by-step explanation:

Rise over run. you go up 2 and right 4

5 0
3 years ago
Read 2 more answers
Work out 5/8 x 2 please help quick
Fed [463]
5/8 * 2 = 

10/8 =

5/4
-------------------

your answer is 5/4
4 0
3 years ago
If 4 coins are tossed simultaneously what is the probability of getting exactly 3 heads
Alexus [3.1K]
No of outcomes =16
favourable outcome=4
<span>probability of getting exactly 3 heads=0.25</span>
6 0
3 years ago
34. For the following exercises, given each set of information, find a linear equation satisfying the conditions, if possible.
skad [1K]

Answer:

The linear equation for the line which passes through the points given as (-1,4) and (5,2), is written in the point-slope form as $y=\frac{1}{3} x-\frac{13}{3}$.

Step-by-step explanation:

A condition is given that a line passes through the points whose coordinates are (-1,4) and (5,2).

It is asked to find the linear equation which satisfies the given condition.

Step 1 of 3

Determine the slope of the line.

The points through which the line passes are given as (-1,4) and (5,2). Next, the formula for the slope is given as,

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substitute 2&4 for $y_{2}$ and $y_{1}$ respectively, and $5 \&-1$ for $x_{2}$ and $x_{1}$ respectively in the above formula. Then simplify to get the slope as follows,

m=\frac{2-4}{5-(-1)}$\\ $m=\frac{-2}{6}$\\ $m=-\frac{1}{3}$

Step 2 of 3

Write the linear equation in point-slope form.

A linear equation in point slope form is given as,

$y-y_{1}=m\left(x-x_{1}\right)$

Substitute $-\frac{1}{3}$ for m,-1 for $x_{1}$, and 4 for $y_{1}$ in the above equation and simplify using the distributive property as follows,

y-4=-\frac{1}{3}(x-(-1))$\\ $y-4=-\frac{1}{3}(x+1)$\\ $y-4=-\frac{1}{3} x-\frac{1}{3}$

Step 3 of 3

Simplify the equation further.

Add 4 on each side of the equation $y-4=\frac{1}{3} x-\frac{1}{3}$, and simplify as follows,

y-4+4=\frac{1}{3} x-\frac{1}{3}+4$\\ $y=\frac{1}{3} x-\frac{1+12}{3}$\\ $y=\frac{1}{3} x-\frac{13}{3}$

This is the required linear equation.

5 0
2 years ago
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