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Mkey [24]
3 years ago
7

Find the volume of the regular hexagonal prism with side lengths of 4 ft, height of 3ft and apothem of approximately 3.5 ft

Mathematics
1 answer:
nexus9112 [7]3 years ago
3 0

Answer:

A(p)  = 84 ft³

Step-by-step explanation:

Volume of regular prism is equal to V(p):

V(p)  = Area of the face * h

we know h = 3 ft

A regular hexagonal prism has 6 equal sides forming its face.

Finding the area (A₂) of a triangle formed  by center of the prism, straight lines between the center and two adjacents vertex and side between these two vertex, and then multiply that area by 6 (number of equal triangles inside hexagonal prism) we get the area of the face, but  we need further consideration, the triangle described above, has doble area of (A₁), the triangle formed by apothem, half side, and straight line between center of the face and the vertex, therefore.

Area of small triangle = base * height

A₁  = (1/2) * 4 * 3,5

A₁  =  2*3,5

A₁  = 7 ft²

A₂  = 2* 7    

A₂  = 14 ft²

Finally volume  of the hexagonal prism is:

V(p) = 6 * 14

A(p)  = 84 ft³

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Use the following information for problems 1 – 3. Suppose you sign a contract for an annual salary of $50,000 with a guaranteed
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7 0
3 years ago
How do I do question 9? Please give answer thank you
kvasek [131]
<h3>Given</h3>
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  • filling at the rate 0.004 m³/s
  • fill height of 0.2 m at the time of interest
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This area multiplied by the rate of change of fill height (dh/dt) will give the rate of change of volume.

... (0.09π/16 m²)×dh/dt = dV/dt = 0.004 m³/s

Dividing by the coefficient of dh/dt, we get

... dh/dt = 0.004·16/(0.09π) m/s

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dh/dt = .004·64/(.04·9·π) = 32/(45π)

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