Given that the graph shows tha the functión at x = 0 is below the y-axis, the constant term of the function has to be negative. This leaves us two possibilities:
y = 8x^2 + 2x - 5 and y = 2x^2 + 8x - 5
To try to discard one of them, let us use the vertex, which is at x = -2.
With y = 8x^2 + 2x - 5, you get y = 8(-2)^2 + 2(-2) - 5 = 32 - 4 - 5 = 23 , which is not the y-coordinate of the vertex of the curve of the graph.
Test the other equation, y = 2x^2 + 8x - 5 = 2(-2)^2 + 8(-2) - 5 = 8 - 16 - 5 = -13, which is exactly the y-coordinate of the function graphed.
Then, the answer is 2x^2 + 8x -5
First you have to make the assumption that these are the only two outcomes. There is also the possibility of hitting the ball and getting out.
However, if we assume that these are the only two cases, we know that the probability is 58.3%. This is because it has been on base 7 times out of 12.
Answer:
- X'(5, 2)
- Y'(0, 1)
- Z'(-1, -4)
Step-by-step explanation:
The translation increases each x-coordinate by 3, moving the point 3 units to the right. It decreases each y-coordinate by 1, moving the point 1 unit down.
(x, y) ⇒ (x+3, y-1)
X(2, 3) ⇒ X'(5, 2)
Y(-3, 2) ⇒ Y'(0, 1)
Z(-4, -3) ⇒ Z'(-1, -4)
The red arrows show the translation of each point in the graph.
<h3>
Answer: -4</h3>
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Explanation:
We can pick any two rows from the table to get the (x,y) points needed to find the slope.
Let's say we pick the second and third rows
Subtract the y values: 14-6 = 8
Subtract the x values in the same order: 1-3 = -2
Divide the differences: 8/(-2) = -4
The slope is -4
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You can use the slope formula
Let's say the points are (x1,y1) = (1,14) and (3,6)
m = (y2-y1)/(x2-x1)
m = (6-14)/(3-1)
m = -8/2
m = -4
It's the same basic idea as the previous section. You subtract the y values together (y2-y1) and the x values together (x2-x1) and divide the differences to get m. The order of subtraction doesn't matter as long as you stay consistent. If you do something like y2-y1 and x1-x2, then you'll get the wrong slope value.
Answer:
D. 
Step-by-step explanation:
The point-slope form of a line is given by:
The line given to us has equation; 
.
The slope of this line is -4. The of the line perpendicular to this line is the negative reciprocal of the slope of the given line.
Our slope of interest is therefore; 
Since the point goes through (-2,7), we have 
.
We plug in the slope and the point into the point-slope formula to obain;
The required equation is:
