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4 years ago

5

Use the graph of the exponential growth function f(x) = a(2x) to determine which statement is true. f(0) = 2 when a =1/2 . f(0)

= 3 when a = 3. f(1) = 9 when a = 9.

2 answers:

Svet_ta [14]4 years ago

8 0

Please Rate 5 stars and Thanks this, I'm doing an experiment.

Kryger [21]4 years ago

3 0

Math symbols were invented for a reason. They help communicate your intent. Here, it looks like you may intend

... f(x) = a(2^x)

When x=0, this will have the value "a". When x=1, this will have the value a^2. The appropriate selection is

... f(0) = 3 when a = 3

You might be interested in

What is the least common multiple of 8, 9 and 10

aleksandr82 [10.1K]

The least common multiple of 8,9, and 10 is 360

8 0

4 years ago

Read 2 more answers

4+7a=12+8a<br> with steps pls

Varvara68 [4.7K]

Answer:a=-8

Step-by-step explanation:

4+7a=12+8a

So first you want to have the variables on the same side

4+7a-7a=12+8a-7a

This is how you got the 7a to the right side. Then you subtract 8a-7a So the equation becomes

4=12+a

Now there are two ways of doing this.

1. 4-12=12-12+a

You moved the 12 to the left side so you have the same variable on one side

4-12=-8

So then a=-8

Or

2. 4-4=12-4+a

0=8+a

then you would have to subtract 8 to keep 'a' by itself

-8=8-8+a

simplify it

-8=a

same thing

3 0

3 years ago

Read 2 more answers

Below are the solutions for a variable "x." State the solution that matches the graph below.

Aloiza [94]

We have a number line as indicated in the figure above. From this figure we know that the <em>x-values</em> <em>increase f</em><em>rom left to right</em>. So we need to write the solution<span> that matches the previous graph. Taking a look on the graph we see that $x$ begins in -3 and closes in 8, that is, $x$ <em>takes values from -3 to 8</em>. In a mathematical language this is given by the following statement:

</span> $x \in [-3,8]$ <span>

</span>

7 0

4 years ago

Solve 5x^3 - 3x^2 - 14x

Pie

<h3>I’ll teach you how to solve 5x^3 - 3x^2 - 14x</h3>

--------------------------------------------------------

5x^3 - 3x^2 - 14x

Factor out the common term x:

x(5x^2 - 3x 14)

Factor 5x^2 - 3x 14:

Break the expression into groups:

(5x62+7x)+(-10x-14)

Factor out x from 5x^2+7x:

x(5x+7)

Factor out -2 from -10x-14:

-2(5x+7)

x(5x+7)-2(5x+7)

Factor out the common term 5x+7:

(5x+7)(x-2)

x(x+7)(x-2)

Your Answer Is x(x+7)(x-2)

Plz mark me as brainliest :)

7 0

4 years ago

What is the solution to the system of linear equations?<br><br> −9x+4y=55<br><br> −11x+7y=82

LuckyWell [14K]

Here is my process with mathematical expression interpreter, LaTeX. Full process given below to obtain the values of variable "x" and "y" altogether, solutions to these system of linear equations.

$\begin{bmatrix}-9x & + & 4y & = & 55 & \bf{- - - \: Eq. \: 1} \\ \\ -11x & + & 7y & = & 82 & \bf{- - - \: Eq. \: 2} \end{bmatrix}$

Now here, we should isolate a variable, or take it as a separate form to find the equation, and furthermore substitute the value of variable "y" into the original isolation of "x", to obtain both the solutions for this linear system of equation. Perform this on equation number 1 (Eq. 1).

Subtract the variable attached value by "4y" on both the sides, in current expression.

$\mathbf{-9x + 4y - 4y = 55 - 4y}$

$\mathbf{-9x = 55 - 4y}$

Both the sides, perform a division of value "-9".

$\mathbf{\dfrac{-9x}{-9} = \dfrac{55}{-9} - \dfrac{4y}{-9}}$

$\mathbf{x = \dfrac{55 - 4y}{-9}}$

$\mathbf{x = - \dfrac{55 - 4y}{9}}$

Substitute or just plug the value of newly obtained expression for variable "x" into Equation, numbered as "2" (Eq. 2.) and isolate further for the variable "y", to obtain first solution for this linear equation.

$\mathbf{-11 \Bigg(- \dfrac{55 - 4y}{9} \Bigg) + 7y = 82}$

$\mathbf{\dfrac{(55 - 4y) \times 11}{9} + 7y = 82}$

Multiply both the sides by a value of "9".

$\mathbf{\dfrac{(55 - 4y) \times 11}{9} + 7y \times 9 = 82 \times 9}$

$\mathbf{11 (55 - 4y) + 63y = 738}$

$\mathbf{605 - 44y + 63y = 738}$

$\mathbf{605 + 19y = 738}$

Subtract both the sides by a value of "- 605".

$\mathbf{605 + 19y - 605 = 738 - 605}$

$\mathbf{19y = 133}$

Divide both the sides by "19".

$\mathbf{\dfrac{19y}{19} = \dfrac{133}{19}}$

$\boxed{\mathbf{y = 7}}$

Substitute this variable value of "y = 7" , into our original isolation for variable "x", the expression is to be substituted by that value to complete the solutions for the linear equations. That is:

$\mathbf{x = - \dfrac{55 - 4y}{9}; \quad y = 2}$

$\mathbf{\therefore \quad x = - \dfrac{55 - 4 \times 7}{9}}$

$\mathbf{\therefore \quad x = - \dfrac{55 - 28}{9}}$

$\mathbf{x = - \dfrac{27}{9}}$

$\boxed{\mathbf{x = - 3}}$

Finalised solutions for these linear system of equations for two components , is:

$\boxed{\mathbf{\underline{\therefore \quad Final \: Solutions \: for \: these \: System \: of \: Linear \: Equations: \: x = - 3, \: \: y = 7}}}$

Hope it helps.

5 0

3 years ago