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lesya [120]
3 years ago
9

19​-foot ladder is placed against a vertical wall of a​ building, with the bottom of the ladder standing on level ground 11 feet

from the base of the building. How high up the wall does the ladder​ reach?
Mathematics
2 answers:
vlabodo [156]3 years ago
7 0
Pythagorean Theorem
c2 = a2 + b2
19^2 = a^2 + 11^2
361 = a^2 + 121
240 = a^2
A = 15.49
alexandr1967 [171]3 years ago
6 0
It is approximately 15.5 feet. to find this you want to use the Pythagorean theorem. which is a^2+b^2=c^2. 19 is the hypotenuse, 11 is leg a. so to find the other leg square both 19 and 11. to get 361 and 121. so now you have 121+b^2=361. subtract 121 from 361 and you end up with b^2 which is 240. find the square of 240 which in decimal is 15.4919333 etc. so rounding it is 15.5. and exact answer is square root of 4*60 which is 2square root 60. hope I helped you!
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