6. Line a: y - 3x = 4 Line b: y = 3x + 5 Line c: y - 4x = 3 Which lines are parallel

Find an equation of the line passing through the point (2, -3) and has slope -4. Then rewrite your linear equation in the slope-

Tresset [83]

Answer:

y=-4x+5

Step-by-step explanation:

y+3=-4(x-2)

y+3=-4x+8

-3. -3

y=-4x+5

8 0

2 years ago

F(x) = x2. What is g(x)?

puteri [66]

Answer:

C: g(x) = 3x^2

Step-by-step explanation:

Note that (1, 1) is on the graph of f(x) and that (1, 3) is on the graph of g(x). This indicates that the coefficient of x^2 is 3 for g(x).

5 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B%20lnx%20%7D%20" id="TexFormula1" title=" \sqrt[4]{ lnx } " alt=" \sqrt[4]

Kamila [148]

Use the power rule for differentiation:

$\dfrac{\text{d}}{\text{d}x} (f(x))^k = k(f(x))^{k-1}f'(x)$

You can use this formula if you remember that a root is just a rational exponential:

$\sqrt[4]\ln(x) = (\ln(x))^{\frac{1}{4}}$

So, remembering that the derivative of the logarithm is 1/x, you have

$\dfrac{\text{d}}{\text{d}x} (\ln(x))^{\frac{1}{4}} = \frac{1}{4}(\ln(x))^{\frac{1}{4}-1}\dfrac{1}{x}$

Which you can rewrite as

$\dfrac{1}{4}(\ln(x))^{\frac{1}{4}-1}\dfrac{1}{x} =\dfrac{1}{4}(\ln(x))^{\frac{-3}{4}}\dfrac{1}{x} =\dfrac{1}{4}\dfrac{1}{\sqrt[4]{\ln(x))^3}}\dfrac{1}{x} = \dfrac{1}{4x\sqrt[4]{\ln(x))^3}}$

3 0

2 years ago

Factorise P(x)= (x+3)(12x^2-3)+(2x-1)(x^2-9) And Q(x)= 4x^4-x^2

Archy [21]

Answer:

a2 answers to exercises

ii. yes. suppose a is negative, so write a = -b where b is positive. let c be a

positive number such that c" = b. then (-c)" = a because (-1)" = -1 since

n is odd.

ii, §1, p. 24

3. x negative, y positive 4. x negative, y negative

ii, §3, p. 33

5. y = -~x + i 6. y = -ix + s 7. x = j2

9 9j3 8. y = --;:;- x + 4 - --;:;- 9. y = 4x - 3 10. y = -2x + 2

",3+3 ",3+3

ii. y= -!x+3+ j'!- 12. y=j3x+s+j3 19. -! 20.-8

21. 2 + j2 22.!<3 + j3) 23. y = (x - n>(j22_ n) + 1

24. y=(x-j2)c~-~)+2 25. y= -(x+ l)(j23+ 1)+2

26. y = (x + 1)(3 + j2) + j2 29. (a) x = -4, y = -7 (b) x = ~, y = i

(c) x = -!, y = 1 (d) x = - 6, y = - 5

ii, §4, p. 35

1.j97 2.j2 3.js2 4.ji3 5.!j5 6.(4,-3) 7. sands 8.(-2,5)

9. sand 7

ii, §8, p. 51

5. (x - 2)2 + (y + 1)2 = 25 6. x 2 + (y - 1)2 = 9 7. (x + \)2 + y2 = 3

8. y + ¥ = 2(x + w 9. y - 1 = (x + 2)2 10. y + 4 = (x - \)2

ii. (x + 1)2 + (y - 2)2 = 2 12. (x - 2)2 + (y - \)2 = 2

13. x + ¥- = 2(y + !)2 14. x-i = (y + 2)2

iii, §1, p. 61

1. 4 2. -2 3. 2 4. i s. -! 6. 0 7. 4 8. 6 9. 3 10. 12 ii. 2

12. 3 13. a

8 0

2 years ago

Read 2 more answers

Which value of a in the exponential function below would cause the function to shrink? f(x) = a(three-halves) Superscript x Four

Natalka [10]

Answer:

Four-fifths

Step-by-step explanation:

As we know that

By multiplying the function by a constant, we may expand or shrink the function in the y-direction.

Now we have

$y=a(b^{x})$

if $a> 1$ > the function would enlarge

if $0< a < 1$ > the function would shrinks

Now

For case A

$a = \frac{4}{5}$

$0 < (\frac{4}{5} )< 1$ ....... > the function would shrinks

For case B

$a = \frac{5}{4}$

$(\frac{5}{4} )>1$ .......> the function would enlarge

For case C

$a = \frac{3}{2}$

$(\frac{3}{2} )>1$ .........> the function would enlarge

For case D

$a = \frac{7}{4}$

$(\frac{7}{4} )>1$ .........> the function would enlarge

Therefore the second option is correct

5 0

3 years ago

Read 2 more answers