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zaharov [31]
3 years ago
12

If you invest in a mutual fund that pays annual interest compounded monthly over 5 years, what annual interest rate is needed to

double your invest in 5 year?​
Mathematics
1 answer:
grigory [225]3 years ago
4 0

Answer:

Step-by-step explanation:

This may seem a bit tricky because we are not given enough info really to plug in and solve for the rate.  We are told, however, that we are interested in doubling whatever amount we invested.  So it is up to us to pick an amount for P, then double it for A(t).  Let's use P = 1000 so A(t) = 2000.  Filling in then:

2000=1000(1+\frac{r}{12})^{(12)(5)} and

2000=1000(1+\frac{r}{12})^{60}

We need to get that r all by itself and right now it's quite buried.  Begin by dividing both sides by 1000 to get

2=(1+\frac{r}{12})^{60}

Now take the 60th root of both sides to get

1.01161944=1+\frac{r}{12}

Subtract 1 from both sides to get

.01161944=\frac{r}{12} and multiply both sides by 12 to finally get the rate in decimal form:

r = .13943328

To get that in a percent form, multiply it by 100:

r = 13.9%

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F(x) = <img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%2B7%7D%20-%5Csqrt%7Bx%5E2%2B2x-15%7D" id="TexFormula1" title="\sqrt{x+7} -\
elena-s [515]

Answer:

x >= -7  ................(1a)

x >= 3   ...............(2a1)

Step-by-step explanation:

f(x) =  \sqrt{x+7}-\sqrt{x^2+2x-15}  .............(0)

find the domain.

To find the (real) domain, we need to ensure that each term remains a real number.

which means the following conditions must be met

x+7 >= 0  .....................(1)

AND

x^2+2x-15 >= 0 ..........(2)

To satisfy (1),  x >= -7  .....................(1a) by transposition of (1)

To satisfy (2), we need first to find the roots of (2)

factor (2)

(x+5)(x-3) >= 0

This implis

(x+5) >= 0 AND (x-3) >= 0.....................(2a)

OR

(x+5) <= 0 AND (x-3) <= 0 ...................(2b)

(2a) is satisfied with x >= 3   ...............(2a1)

(2b) is satisfied with x <= -5 ................(2b1)

Combine the conditions (1a), (2a1), and (2b1),

x >= -7  ................(1a)

AND

(

x >= 3   ...............(2a1)

OR

x <= -5 ................(2b1)

)

which expands to

(1a) and (2a1)   OR  (1a) and (2b1)

( x >= -7 and x >= 3 )  OR ( x >= -7 and x <= -5 )

Simplifying, we have

x >= 3  OR ( -7 <= x <= -5 )

Referring to attached figure, the domain is indicated in dark (purple), the red-brown and white regions satisfiy only one of the two conditions.

3 0
3 years ago
Read 2 more answers
the red line and the blue line trains just arrived at station when will they next arrive at the station at the same time
Whitepunk [10]
They will meet back up in 40 minutes because 8x5=40 and 10x4=40 which 40 is both a multple of 8 and 10 so you're welcome
4 0
3 years ago
K+ 6 ≥ 19, if k = 11
WINSTONCH [101]

Answer:

Then it would be the other way around 19 ≥ k + 6

Wait for more responses if needed.

4 0
3 years ago
Read 2 more answers
G(x)=3^x +1 and f(x)=3x+1 which values of x makes f(x) =g(x) true
fomenos

Answer:

x=1

Step-by-step explanation:

3^x +1

f(x)=3x+1

f(x) =g(x)

3x +1 =3^x +1

Subtract 1 from each side

3x = 3^x

Let x =1

3*1 = 3^1

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5 0
3 years ago
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1/8 of the boys at a high school tried out for the football team, 1/6 tried out for the baseball team, and 1/ 12 tried out for t
Xelga [282]

Answer:

2/3

Step-by-step explanation:

This problem is an overlap problem. First we have that 1/8 total tried out for football team, 1/6 total tried out for baseball team and 1/12 of the students that tried out for both football and baseball team.

So if we want to find those who just tried football, we perform the following operation:

1/8 - 1/12 = 1/24.

So we know that 1/24 tried out just football.

If we want to find all those who tried out just for baseball, we perform the following operation:

1/6 - 1/12 = 1/12

So we know that 2/24 (1/12 multiplied by two) tried  for both football and baseball and 3/24 tried out for football, it means that 2/3 of the boys who tried football also tried baseball.

7 0
3 years ago
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