Answer:
the answer is 32 to the 3rd power
Step-by-step explanation:
Answer:
0.0032
The complete question as seen in other website:
There are 111 students in a nutrition class. The instructor must choose two students at random Students in a Nutrition Class Nutrition majors Academic Year Freshmen non-Nutrition majors 17 18 Sophomores Juniors 13 Seniors 18 Copy Data. What is the probability that a senior Nutrition major and then a junior Nutrition major are chosen at random? Express your answer as a fraction or a decimal number rounded to four decimal places.
Step-by-step explanation:
Total number of in a nutrition class = 111 students
To determine the probability that the two students chosen at random is a junior non-Nutrition major and then a sophomore Nutrition major, we would find the probability of each of them.
Let the probability of choosing a junior non-Nutrition major = Pr (j non-N)
Pr (j non-N) = (number of junior non-Nutrition major)/(total number students in nutrition class)
There are 13 number of junior non-Nutrition major
Pr (j non-N) = 13/111
Let the probability of choosing a sophomore Nutrition major = Pr (S N-major)
Pr (S N-major)= (number of sophomore Nutrition major)/(total number students in nutrition class)
There are 3 number of sophomore Nutrition major
Pr (S N-major) = 3/111
The probability that the two students chosen at random is a junior non-Nutrition major and then a sophomore Nutrition major = 13/111 × 3/111
= 39/12321
= 0.0032
Answer:
By the triangle side length theorem, the sum of the two shorter sides has to be equal to or larger than the third side. Thus, we can write the following inequation.
a
+
b
≥
c
, where a and b are the shorter sides and c the longest.
11, 9 and 15 satisfies this inequality while 11, 9 and 20 doesn't.
Justification:
The reason for this rule is simple; it's because if the longest side is longer than the sum of the two shorter sides, this means that the shorter sides aren't long enough to connect with the longest side, thus rendering the shape a collection of lines and disqualifying the possibility of having a triangle, which was our objective.
Practice exercises:
Which of the following triangles is possible?
a) 4,6 and 14
b) 5,11 and 16
c) 1,3,6
D). 12,19 and 26
Find the smallest possible value of a to make the following an actual triangle :
a
,
14
,
25
Hopefully this helps:
Step-by-step explanation:
Step-by-step explanation:
Sin<D = Opposite / Hypotenuse
Opposite - EC
Hyp - DE
Sin<D = EC/DE = x/9
we need x to find <D.
so -->Use pythagorean theorem.
DE^2 = EC^2 + DC^2
DE = 9 DC = 7 EC = ?
EC^2 = DE^2 - DC^2 rearranged.
= 9^2 - 7^2
= 81 - 49
EC^2 = 32 Put both sides under square root.
√(EC^2) = √32
EC = 4√2 ~ 5.65.
We now have X which was representing the unknown side EC.
Sin<D = EC/DE = 5.65/9 = 0.627
To find <D Take the sine inverse of of 0.627.
<D = Arcsin(0.627) = 38.82°.
We now know <D. It's <E's turn.
A right angle triangle has a summation of interior angles of 180°.
thus, <em><D + <C + <E = 180°</em>
38.82° + 90° + <E = 180°
128.82° + <E = 180°
subtract both sides by 128.82°
0 + <E = 180° - 128.82°
<em><E = 51.</em><em>2</em><em>°</em>
I think it is 0.149x10^-4
