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kakasveta [241]
3 years ago
6

!!WILL UP VOTE!!

Mathematics
1 answer:
myrzilka [38]3 years ago
4 0
<span>3. subtract 3
that's the next step</span>

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Given A-<br> 2 2<br> 1 3<br> what is A-¹?
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The inverse of matrix A = \left[\begin{array}{cc}2&2&1&3\\\end{array}\right] is A^{-1} = \frac{1}{4} \left|\begin{array}{cc}3&-2&-1&2\\\end{array}\right|      

The given matrix is A = \left[\begin{array}{cc}2&2&1&3\\\end{array}\right]

The inverse of a matrix is given by

A^{-1} = \frac{1}{|A|} adjA                   ...(1)

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|A| = \left|\begin{array}{cc}2&2&1&3\\\end{array}\right|

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Now, adjoint A will be

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A_{22} = 2

AdjA = \left|\begin{array}{cc}3&-2&-1&2\\\end{array}\right|

Now, substituting the values of |A| and AdjA in equation (1), we get

A^{-1} = \frac{1}{4} \left|\begin{array}{cc}3&-2&-1&2\\\end{array}\right|        

Therefore, A^{-1} = \frac{1}{4} \left|\begin{array}{cc}3&-2&-1&2\\\end{array}\right|      

Know more about Inverse of Matrix: -brainly.com/question/12442362

#SPJ9

     

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