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Genrish500 [490]
3 years ago
12

Solve 1 - 12 or any question please

Mathematics
1 answer:
ZanzabumX [31]3 years ago
4 0
There two forms to write an equation in; slope-intercept form, <em /><em>y</em> = <em>mx</em> + <em>b</em>, where <em>m</em> is the slope and <em>b</em> is the <em>y</em>-intercept; and point-slope form, which is given by y-y_1=m(x-x_1), where <em>m</em> is the slope and (<em>x</em>₁, <em>y</em>₁) is a point on the line.  Given the information and instructions you have I assume you need point-slope form.  For #1, you have <em /><em>m</em> = 2 and point (3, 5).  Substitute these values in:
y-5=2(x-3)
If you need slope-intercept form, you start by using the distributive property on what you just wrote:
y-5=2*x-2*3&#10;\\y-5=2x-6
Now cancel the 5 to isolate <em>y</em>:
y-5+5=2x-6+5&#10;\\y=2x-1
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PLEASE HELP! I have a deadline tonight ,I have to get this done! thank you!!<br> Two questions (:
Viktor [21]
Both of your answers are correct. In the first equation, if you were to substitute 3 for x, because you have to do exponents first, you have 3^2, which is 9, and 9*6 =54. If you were to substitute -3 for x again you would have to do the exponents first which would be -3^2 which is 9, and 9*6 = 54. 

For the second question, if I substitute 0.75 for t, I get -9 + 18 + 7. This is equal to 16, and therefore the answer would be D. Hope this helps! :D. Let me know if you have questions about my explanation, and feel free to post more questions.
3 0
3 years ago
Kate is taking a short break and wants to pick up lunch from her favorite drive-thru restaurant, Burger Shack. There are two loc
Veronika [31]

Answer:

B.) Beachside Sqaure

Step-by-step explanation:

The reason why is because, you have to look at her intentions and the time frame she wants to wait for food at these restaurants. Beachside Sqaure has less times they have made her wait for her food more than 10 minutes, so that would be their advantage.

6 0
2 years ago
Simplify the following expression. cot^2x secx-cosx
Solnce55 [7]

ANSWER

\cos(x)   \cot ^{2} (x)

EXPLANATION

The given expression is;

\cot^{2} (x)  \sec(x)  -  \cos(x)

Change everything to

\sin(x)

and

\cos(x)

This implies that,

\frac{ \cos^{2} (x) }{ \sin^{2} (x) }  \times ( \frac{1}{ \cos(x) } )-  \cos(x)

Cancel the common factors,

\frac{ \cos(x) }{ \sin^{2} (x) }  \times ( \frac{1}{1} )-  \cos(x)

\frac{ \cos(x) }{ \sin^{2} (x) }-  \cos(x)

\frac{ \cos(x)  -  \sin ^{2} (x)  \cos(x) }{ \sin^{2} (x) }

= \frac{ \cos(x)(1  -  \sin ^{2} (x) ) }{ \sin^{2} (x) }

= \frac{ \cos(x)(\cos^{2} (x) ) }{ \sin^{2} (x) }

= \cos(x)  \cot^{2} (x)

6 0
3 years ago
How to turn a mixed number into an improper fraction?
disa [49]
To turn a mixed number into an improper fraction, multiply the bottom number of the fraction, or the denominator by the whole number, and then add the top number of the fraction to that number. Put the number you get over the denominator For example:

2 1/4⇒ 4 x 2=8    8+1= 9  

9/4 would be your improper fraction
7 0
3 years ago
Solve for x ax + b = r ​
nataly862011 [7]

Answer:

ax+b=r

ax=r-b

x=(r-b)/a

Step-by-step explanation:

3 0
3 years ago
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