Can u help me from 1-3 SHOWING all the work also please
1 answer:
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Answer:a) a=22, b=11
b) m=7, n=
Step-by-step explanation:
You should use trigonometry ratios as required and then you should use pythagoras theorem
In a) cosine(30°)= base/hypotenuse,
where 11√3 is the base
"a" is hypotenuse and
"b" is perpendicular
from this you can find the value of perpendicular then you should use pythagoras theorem to find the value of hypotenuse
pythagoras theorem is
base²+perpendicular²= hypotenuse²
Same is applied on (b) right triangle as, sine(45°)=perpendicular/hypotenuse
Answer:
<em>The biggest profit that can be obtained by the shop owner= </em>IDR 2,750,000.
Step-by-step explanation:
We need to form a LPP( Linear Programming Problem) for the following problem and solve it to get the maximize the profit.
Let x denote the number of men's shoe and y denote the number of female shoes.
Maximize z= 10000x+5000y----------(1)
x≥100 ( since a shoe store owner wants to fill his shop with at least 100 pairs of men's shoes )
y≥150 (at least 150 pairs of women's shoes).
also x+y≤400 (The store can only accommodate 400 pairs of shoes).
x≤150 (male shoes should not exceed 150 pairs).
⇒ 100≤x≤150
Hence the optimal solution of an LPP always lie on the end points.
We have end points as:
(100,300), (150,250), (100,150),(150,150).
by putting these value in equation (1) we see which give the maximum solution.
for (100,300) i.e. x=100 and y=300: z=2,500,000
for (150,250) i.e. x=150 and y=250: z=2,750,000
for (100,150) i.e. x=100 and y=150: z=1,750,000
for (150,150) i.e. x=150 and y=150: z=2,250,000
Hence maximum profit is obtained at x=100 and y=300.
i.e. to maximize the profit:
<em>Number of men's shoes to be kept in store=100</em>
<em>and number of women's shoes to be kept in store=300</em>
<em>The biggest profit that can be obtained by the shop owner= </em>IDR 2,750,000.
