Answer:
5) arccos A = 28°
6) arcsin A = 53°
Step-by-step explanation:
5) cos A = 30/34
6) sin A = 32/40
The work done in pushing the box is 64000 lb-ft²/s²
<h3>How to calculate the work done by the person?</h3>
Since person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long, the work done, W is
W = mgh where
- m = mass of box = 40 lb,
- g = acceleration due to gravity = 32 ft/s² and
- h = height of incline = LsinФ where
- L = length of incline = 100 ft and
- Ф = angle of incline = 30°
So, W = mgh
W = mgLsinФ
So, substituting the values of the variables into the equation, we have
W = mgLsinФ
W = 40 lb × 32 ft/s² × 100 ftsin30°
W = 1280 lb-ft/s² × 100 ft × 0.5
W = 1280 lb-ft/s² × 50 ft
W = 64000 lb-ft²/s²
So, the work done in pushing the box is 64000 lb-ft²/s²
Learn more about work done here:
brainly.com/question/25970931
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Answer:
64 teachers
Step-by-step explanation:
We can use ratios to solve
14 students 896 students
----------------- = -------------
1 teacher x teachers
Using cross products
14 * x = 896*1
Divide each side by 14
14x/14 = 896/14
x =64
Answer:
your answer will be
A)(6,10)
B)(2,12)
C)(4,4)
Step-by-step explanation:
hope this helps
have a nice day/night ^_^
Answer:
x=9
Step-by-step explanation:3x-5+x=31
3x+x=31+5
4x=36
x=36/4
x=9
