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Lerok [7]
3 years ago
9

In a certain town there were 243 robberies last year. This year the number of robberies has gone down 28%. How many robberies we

re there this year, to the nearest whole number?
Mathematics
2 answers:
VladimirAG [237]3 years ago
7 0

Answer: 175 robberies

Step-by-step explanation:

Robberies last year= 243

Robberies has reduced by 28% which means there are (100-28)% = 72% robberies this year.

Number of robberies this year= 72% of 243 = 72/100 × 243 = 174.96 = 175.

There are 175 robberies this year

Leviafan [203]3 years ago
6 0

Answer: 175

Step-by-step explanation:

The original number of robberies = 243

It has been reduced by 28% , to find the present number of robberies , all we need do is to find 72% of 243. That is

72% x 243

= 0.72 x 243

= 174.96

Therefore , the number of robberies this year to the nearest whole number will be 175

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Detmermine the best method to solve the following equation, then solve the equation. (3x-5)^2=-125
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For the given equation;

(3x-5)^2=-125

We shall begin by expanding the parenthesis on the left side, after which we would combine all terms on and move all of them to the left side, which shall yield a quadratic equation. Then we shall solve.

Let us begin by expanding the parenthesis;

\begin{gathered} (3x-5)^2\Rightarrow(3x-5)(3x-5) \\ (3x-5)(3x-5)=9x^2-15x-15x+25 \\ (3x-5)^2=9x^2-30x+25 \end{gathered}

Now that we have expanded the left side of the equation, we would have;

\begin{gathered} 9x^2-30x+25=-125 \\ \text{Add 125 to both sides and we'll have;} \\ 9x^2-30x+25+125=-125+125 \\ 9x^2-30x+150=0 \end{gathered}

We shall now solve the resulting quadratic equation using the quadratic formula as follows;

\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \text{Where;} \\ a=9,b=-30,c=150 \\ x=\frac{-(-30)\pm\sqrt[]{(-30)^2-4(9)(150)}}{2(9)} \\ x=\frac{30\pm\sqrt[]{900-5400}}{18} \\ x=\frac{30\pm\sqrt[]{-4500}}{18} \\ x=\frac{30\pm\sqrt[]{-900\times5}}{18} \\ x=\frac{30\pm\sqrt[]{-900}\times\sqrt[]{5}}{18} \\ x=\frac{30\pm30i\sqrt[]{5}}{18} \\ \text{Therefore;} \\ x=\frac{30+30i\sqrt[]{5}}{18},x=\frac{30-30i\sqrt[]{5}}{18} \\ \text{Divide all through by 6, and we'll have;} \\ x=\frac{5+5i\sqrt[]{5}}{3},x=\frac{5-5i\sqrt[]{5}}{3} \end{gathered}

ANSWER:

x=\frac{5+5i\sqrt[]{5}}{3},x=\frac{5-5i\sqrt[]{5}}{3}

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Answer:

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