Answer:
460
Step-by-step explanation: multiply all numbers to get your answer
Answer:
x = ±3 sqrt(2)
Step-by-step explanation:
x^2 + x^2=6^2
Combine like terms
2x^2 = 6^2
Divide each side by 2
x^2 = * 6^2/2
Take the square root of each side
sqrt(x^2) =± sqrt( 6^2/2)
Remember that sqrt(a/b) = ±sqrt(a ) /sqrt(b)
x = ±sqrt(6^2)/sqrt(2)
x = ±6 /sqrt(2)
We do not leave square roots in the denominator, so we multiply the top and bottom by sqrt(2)
x = ±6 /sqrt(2) * sqrt(2)/ sqrt(2)
x = ±6 *sqrt(2) /( sqrt(2)*sqrt(2))
x = ±6 sqrt(2) /(2)
x = ±3 sqrt(2)
Answer:
the answer is B
Step-by-step explanation:
Answer:
2x+3y-z²
Step-by-step explanation:
twice a number =2x
thrice a number =3x
minus z²
HOPE THIS HELPS!!!
Answer:
82
Step-by-step explanation:
Let's first figure out what the first number is and use that to solve for the next. The problem states that the numbers are consecutive. So the 2nd number word be 1 plus the first.
The sum of 4 consecutive numbers:
1st = x
2nd = x + 1
3rd = x + 2
4th = x + 3
The sum of 4 consecutive number is 326.
1st + 2nd + 3rd + 4th = 326
x + (x + 1) + (x + 2) + (x + 3) = 326
Combine like terms:
4x + 6 = 326
Then we subtract 6 from both sides to isolate 4x:
4x + 6 - 6 = 326 - 6
4x = 320
Then we divide both sides by 4 to isolate x:
4x/4 = 320/4
x = 80
So the first number is 79
Now to get the second, let's just add 1.
80 + 1 = 81
Let's check if our answer would be correct:
80 + 81 + 82 + 83
= 326
