Answer:
The ship is located at (3,5)
Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III
Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II
To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.
Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9
We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3
Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5
Based on the above, the position of the ship is (3,5).
Hope this helps :)
Answer:
the answers are:x1=-4 and x2=5
L(t)=9-0.5t
t=time in hours,
L(t)=length of candle at time t
(A) substitute t=1,2,3,4,5,6 respectively to get
(1,8.5)
(2,8)
(3,7.5)
(4,7)
(5,6.5)
(6,6)
(B) it is a function because none of the x-values duplicate, (nor the y-values).
(C) If the rate changes to 0.45 "/hr, the relation is still linear.
All linear function with finite slope are functions.
Answer:
Volume of cone = (1/3) * Volume of cylinder
Step-by-step explanation:
Use the formulas
Volume of cone = (1/3)* π r^2 *h
Volume of cylinder = π r^2 *h
Therefore
Volume of cone = (1/3) * Volume of cylinder
It should be the 3rd one but idk for sure. if its not then its the 3rd one
