3 years ago

If ab = 8 and a^2+b^2=16, then what is the value of (a+b)^2

2 answers:

5 0

The answer is 4*sqrt(8)
Attached is my work.

3 0

(a+b)^2= a^2+b^2 +2ab
= 16 + 2 (8)
= 16 + 16
= 32

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= 5^12

5^12/5^12 = 12 - 12 =0

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