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kari74 [83]
4 years ago
11

If you vertically stretch the linear parent function f(x)=x, by a factor of 2, what is the equation of the new function?

Mathematics
1 answer:
pentagon [3]4 years ago
4 0

Answer:

y=2x

Step-by-step explanation:

The condition about stretching is that when the stretch factor is greater than 1, the function will be closer to OY axis; when the stretch factor is between 0 and 1, the function will be closer to OX axis.

We can observe this end result in the attached graphs.

The red line represent the original function and the blue line is y=2x

As we can observe that the condition still holds.

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Please help me, Love you
Anton [14]

Answer:

It would be 750

Step-by-step explanation: You have to divide it by 5 and then times it by 3.

8 0
2 years ago
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Find the value of k if the distance between (2,k) and (6,7) is 4√2 unit​
andreyandreev [35.5K]

Answer:

k = 3

Step-by-step explanation:

We have the distance formula: d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}. We can plug in 4\sqrt{2} = d, x2 = 6, x1=2, y2 = 7, y1 = k.

Then, we can solve the question using some algebra to find that k = 3.

Edit: Here is a step by step:

4\sqrt{2} = \sqrt{(6-2)^2 + (7-k)^2}\\

(4\sqrt{2})^2 = (6-2)^2 + (7-k)^2

32 = (4)^2 + (7-k)^2

32 = 16 + (7-k)^2

32 - 16 =  (7-k)^2

16 =  (7-k)^2

\sqrt{16} =  (7-k)

4 = 7-k

k = 3

4 0
3 years ago
I will make you brainliest <br> solve this
lesya692 [45]

Step-by-step explanation:

question number 2 first part X + 2 is equal to 7 .. x is equal to 7 - 2x is equal to 5 ..second part 3 x minus 1 is equal to 3 x is equal to 23 - 1 = 3x=24 x=24÷3=x=8ans

5 0
3 years ago
What is the dimensions of a box that is 11 lnches long 8 lnches wide and 6 in high
Sergio039 [100]
First you need to multiply 11(8) = 88 then multiply 88(6) = 528 then 528/3 = 176. The answer is 176 inches 
7 0
3 years ago
Two students walk in the same direction along a straight path, at a constant speed - one at .90 m/s and the other at 1.90 m/s.a.
anyanavicka [17]

Answer:

a)The second student arrive 7 minutes and 36 seconds sooner

b)They have to walk 598,51 m

Step-by-step explanation:

Speed= Distance/Time

We are looking for time now

Time = Distance/Speed

First student

Time = 780 m/0.90 m/s=866,66 seconds

Second student

Time = 780 m/1.90 m/s=410,52 seconds

Difference=866,66-410,52= 456,14 seconds

In minutes

Difference= 456,14 seconds /60=7 minutes 36 seconds

Distance=Speed x Time

Speed¹ x Time¹ =Speed² x Time²

Time¹= Time² + 5.50 min

5.50 min =350 seconds

Time²  =Speed¹ x Time¹ /Speed²

Time²  =Speed¹ x (Time² + 350 seconds  ) /Speed²

Time²  =0.9 x (Time² + 350 seconds  ) /1.9

Time²  =0,4737 x (Time² + 350 seconds  )

Time²  =0,4737 Time² + 165,79 seconds

Time²  - 0,4737 Time² = 165,79 seconds

0,5263 Time² = 165,79 seconds

Time² = 165,79 seconds/0,5263 =315,01 seconds

Distance=1,9 x 315,01 seconds = 598,51 m

5 0
3 years ago
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