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lord [1]
3 years ago
8

WATCH OUT FOR LINKS PEOPLE ARE PUTTING INAPPROPRIATE LINKS IN ANSWERS OR COMMENTS. DONT CLICK

Mathematics
1 answer:
Zarrin [17]3 years ago
4 0

Answer: Thanks for notifying everyone

Step-by-step explanation:

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In a right triangle, the acute angles measure 2x+50 and 3x degrees
xenn [34]
2x+50 + 3x= 90 degrees
5x +50 = 90
5x =40
x=8

Angle1= 2(8) +50= 66
Angle2= 3(8)=24

66+24+90= 180
6 0
3 years ago
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Use the recursive formula to answer the question.
Oliga [24]

Answer:

5

Step-by-step explanation:

7 0
2 years ago
SOMEONE PLEASE HELP ME ASAP PLEASE!!!​
Ann [662]
If BC = 12 and CD = 5 then BD = 17. 12 + 5 = 17
6 0
3 years ago
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Help!!!!!!!!!!!!!!!!!!!
Sphinxa [80]

Answer:

  • 1) y = (-2/3)x +2/3
  • 2) y = (6/5)x -23/5
  • 5) y = (-1/6)x +4/3
  • 6) y = x -2

Step-by-step explanation:

A simple, mechanical way to do these (perpendicular lines) is ...

  • replace any constant with 0
  • swap the x- and y-coefficients, negating one
  • for point (h, k), replace x with (x-h) and y with (y-k)
  • solve for y (to get slope-intercept form)

1) 3x -2y = 0 . . . . . step 1

... 2x +3y = 0 . . . . step 2

... 2(x -1) +3(y -0) = 0 . . . . step 3

... 2x -2 = -3y . . . . eliminate parentheses, subtract 3y

... y = (-2/3)x +2/3 . . . . divide by the coefficient of y

2) 6(x -3) -5(y +1) = 0 . . . . after step 3

... 6x -23 = 5y . . . . . . . . . . simplify, add 5y

... y = (6/5)x - 23/5 . . . . . divide by the coefficient of y

5) (x+4) +6(y-2) = 0 . . . . . after step 3

... x -8 = -6y . . . . . . . . . . . simplify, subtract 6y

... y = (-1/6)x +4/3 . . . . . . divide by the coefficient of y

6) (y +5) = (x +3) . . . . . . . after step 3

... y = x -2 . . . . . . . . . . . . subtract 5

3 0
3 years ago
Find the area of the triangle with vertices: Q(-5,5,-3), R(-6,8,-4), S(-8,2,-4).
uysha [10]

Answer:

3.16 square units

Step-by-step explanation:

Find the area of the triangle with vertices: Q(-5,5,-3), R(-6,8,-4), S(-8,2,-4).

Step 1

We find QR and QS

QR = R - Q

= R(-6,8,-4) - Q(-5,5,-3)

= (-1, 3, -1)

QS = S - Q

= S(-8,2,-4) - Q(-5,5,-3)

= (-3, -3, -1)

Step 2

QR × QS

(-1, 3, -1) × (-3, -3, -1)

Using the formula:

a x b = (a2b3 – a3b2)i + (a3b1 – a1b3)j + (a1b2 – a2b1)k

Where a = (a1, a2, a3)

b = (b1, b2, b3)

QR = a

QS = b

(-1, 3, -1) × (-3, -3, -1)

a x b = (a2b3 – a3b2)i + (a3b1 – a1b3)j + (a1b2 – a2b1)k

= ((3 × -1) – (-1×-3))i + ((-1)×-3) – (-1) × -1)j + (-1 × -3) – (3×-3)k

= (-3 - 3)i + (3 – 1)j + (3 – 9)k

= 0i + 2j - 6k = (0,2,-6)

QR × QS = (0,2,-6)

Area of the triangle = √0² + 2² + 6²/ 2

= √0 + 4 + 36/2

= √40/2

= 6.324555320336759 /2

3.1622776602 square units

Approximately = 3.16 square units

7 0
3 years ago
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