Question

Which equation represents a circle that contains the point (–2, 8) and has a center at (4, 0)? Distance formula: StartRoot (x 2 minus x 1) squared + (y 2 minus y 1) squared EndRoot (x – 4)2 + y2 = 100 (x – 4)2 + y2 = 10 x2 + (y – 4)² = 10 x2 + (y – 4)² = 100

Answer 1

Answer:

The answer to your question is:    (x - 4)² + (y)² = 100

Step-by-step explanation:

Data

Circle

Center = (4, 0)

Point = ( -2, 8)

Equations

distance = √(x2 - x1)² + (y2 - y1)²

Circle   (x - h)² + (y - k)² = r²

Process

Find r

                r  = √(x2 - x1)² + (y2 - y1)²

                r =  √(-2 - 4)² + (8 - 0)²

                r = √ (-6)² + (8)²

                r = √ 36 + 64

                r = √ 100

                r = 10

Circle

               (x - 4)² + (y - 0)² = (10)²

               (x - 4)² + (y)² = 100

Answer 2

Answer:

(x - 4)² + (y)² = 100

Step-by-step explanation:cuz