Let 
denote the cumulative distribution function for the standard normal distribution (mean 0, standard deviation 1). Then you're looking for <em>z</em> such that
(a) 
(b) 
(c) 
To get the corresponding <em>z</em>-score for each of 0.70, 0.40, and 0.25, take the inverse CDF of both sides:
(a) 
(b) 
(c) 
The ship sails at 20 km / h.
So
20 km / h x 2 h = 40 km
The boat moves 40 km to the northeast.
Then, in the same way:
20 km / h x 1 h = 20 km.
The ship moves 20 km northwest.
We solve this problem using vectors. In this case, we must perform the sum of two vectors a and b
a) magnitude = 40 km and direction 20 degrees east
b) magnitude = 20 km and direction 10 degrees northwest
In Cartesian coordinates, these vectors are written as:
a) 40sin (20º) i + 40cos (20º) j = 13,68i + 37,59j
b) -20sin (10th) i + 20cos (10th) j = -3,473i + 19,70j
The displacement vector of the ship would be the sum of a + b
a + b = 10,207i + 57,29j Finally, the magnitude of the a + b vector will tell us how far the ship is
√(10.21² + 57.29²) = 58.92km
Answer:y1=log5/log9 and y2=7-3x
Step-by-step explanation:
Answer:
32.9
Step-by-step explanation:
- 4.2 × 7 = 29.4
- Plug 29.4 in: 29.4 - 10.4 ÷ 2 + 2.9 × 3
- 10.4 ÷ 2 = 5.2
- Plug 5.2 in: 29.4 - 5.2 + 2.9 × 3
- 2.9 × 3 = 8.7
- Plug 8.7 in: 29.4 - 5.2 + 8.7
- 29.4 - 5.2 + 8.7 = 32.9
I hope this helps!
