Answer:
the anwser is 12
Step-by-step explanation:
Set each piece = to 56, assuming that the 2 variables for which you are not solving are each equal to 0.
7x -2(0)-14(0) = 56
7x=56 (divide each side by 7)
X = ?
(__, 0, 0)
7(0) - 2y - 14 (0) = 56
-2y = 56 (divide each side by -2)
Y= ?
(0, __ , 0)
7(0) - 2(0) - 14z = 56
-14z = 56 (divide each side by -14)
z = ?
(0, 0, __)
We have the following information:
first urn: 6 green balls and 3 red ones
total: 6 + 3 = 9
second urn: 3 green, 3 white and 3 red
total: 3 + 3 + 3 = 9
third urn: 6 green, 1 white and 2 red
total: 6 + 1 + 2 = 9
a) A green ball is more likely to be obtained, since there are more green balls than red balls, which makes the probability higher.
b) probability of drawing a green, red and white ball.
first urn:
green = 6/9 = 66.66%
red = 3/9 = 33.33%
white = 0/9 = 0%
second urn:
green = 3/9 = 33.33%
red = 3/9 = 33.33%
white = 3/9 = 33.33%
third urn:
green = 6/9 = 66.66%
red = 2/9 = 22.22%
white = 1/9 = 11.11%
c) it would be chosen where the probability of drawing green would be the highest, which means that it would be possible both in the first and in the third ballot box, the probability is equal 66.66%
d) without a green ball, the third ballot box would look like this:
5 green balls, 2 red balls and 1 white ball, with a total of 8.
The probability of drawing would be:
green = 5/8 = 62.5%
red = 2/8 = 25%
white = 1/8 = 12.5%
The distributive property is 15+45 = (10 + 40) + (5+5) = 50 + 10 = 60
Hope this helps you.
Answer:
following are the solution to this question:
Step-by-step explanation:
Please find the complete question in the attached file.
The one-sided limits of F(x) at x = 3 must be equivalent for f(x) to be continuous at x = 3.
So,
In equation a multiply the by -2 and then add in the equation b:
So, the value of 
