Answer:
P(z>1.3) = 0.9032
Step-by-step explanation:
We are given:
Mean = 5000
Standard deviation = 1000
x = 6300
P(x>6300)=?
z-score =?
z-score = x- mean/standard deviation
z-score = 6300 - 5000/1000
z- score = 1300/1000
z-score = 1.3
So, P(x>6300) = P(z>1.3)
Looking at the z-probability distribution table and finding value:
P(z>1.3) = 0.9032
So, P(z>1.3) = 0.9032
D.
1/5 of 65 is
65 × 1 / 5
65 / 5
= 13
65 and 13 add up to 78.
65 is the highest number out of both numbers.
♧
5^x = 5^6
x = 6
hope it helps
