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3 years ago

Why are expressions 3(y-2)+2(y-2) and 5(y-2) equivalent

Mathematics

1 answer:

AlladinOne [14]3 years ago

6 0

3(y-2) + 2(y-2) = 5(y-2)

Both terms have the base (y-2), so they can be added together.
3 + 2 = 5

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What are all numbers proportional to 20/5

maks197457 [2]

Answer: 100/25 and 4/1 and 60/15

Step-by-step explanation:

20/5=4, 100/25=4, 4/1=4, and 60/15=4

8 0

3 years ago

which expression represents purely real numbers and which expression represents non-real complex number?

Lyrx [107]

Answer:

Step-by-step explanation:

Complex numbers are the numbers represented by the expression = a + bi

Here a = real part of the number

bi = imaginary part

a and b are the real numbers.

$i^9=(i^2)^4.(i)$

$=(-1)^{4}.i$ [Since, $i^2=-1$ ]

$=i$

Therefore, its a non real complex number.

2 - $\sqrt{-49}$ = $2-\sqrt{(-1)(7)^2}$

= $2-7\sqrt{-1}$

= $2-7i$

This number is a Non real complex number.

$\sqrt{(-18)^2}=18\sqrt{-1}$

= 18i

It's a non real complex number.

3 + 2i

It's a non real complex number.

-289

It's a purely real number.

$4-32i^2=4-32(-1)$

= 4 + 32

= 36

It's a purely real number.

6 0

2 years ago

Is this table a function? why or why not?

gavmur [86]

No because each time it goes up by (1) and in the last one it goes up (2 times) and then decreases (4 times) on the right.

6 0

3 years ago

When a=3 and b=4, what is the value of 7(a+2b)?<br><br> Solved and worked out

geniusboy [140]

Answer:

Step-by-step explanation:

7 (3 + 2*4) =

7 (3 + 8) =

7 (11) =

7 * 11 =

8 0

2 years ago

A NASA spacecraft measures the rate R of at which atmospheric pressure on Mars decreases with altitude. The result at a certain

AysviL [449]

Answer:

$R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}$

Step-by-step explanation:

For this case we have the following value:

$R = 0.0498 \frac{Kpa}{Km}$

We can convert this first to $\frac{Kpa}{m}$ like this:

$R=0.0498 \frac{Kpa}{Km} *\frac{1km}{1000m}=0.0000498 \frac{Kpa}{m}$

Now we use the fact the the pressure is defined as $P =\frac{F}{A}$ , whre P is the pressure, F the force and A the area, so then $Kpa= \frac{KN}{m^2}$ and then we can replace this:

$R=0.0000498 \frac{KN}{m^3}$

Now from definition of work we know that $W= Fd$ where W is the work, F the force and d the distance, so then is equivalent $KN =\frac{KJ}{m}$

And if we replace this into the equation we got:

$R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}$

4 0

3 years ago