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mezya [45]
3 years ago
5

A chemist has a 100 mL beaker of a 60% solution.

Mathematics
1 answer:
masya89 [10]3 years ago
7 0

Answer:

hi

Step-by-step explanation:

im new here sorry bout not answering it. :)


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On Map 1, which has a scale of 1:25000, length of road is 5.5cm and the area of a park is 1.4cm2
Zolol [24]

Answer:

50 km

Step-by-step explanation:

So the map has a scale of 1 cm: 20 km. Next, you look at how far they are apart and see if the scale and the distance on the map are the same measurement. In this case, they are both centimeters so they stay the same. Then, all you do is multiple the real size, 20 km, by

2.5

1

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4 0
3 years ago
I am stuck on this one and its due tomorrow! Please help
marysya [2.9K]
I believe the error she made was adding it or multipulcation
8 0
3 years ago
How do you solve these problems without numbers
insens350 [35]

i dont know if you want me to answer them or not, but you have to COMBINE LIKE TERMS if you dont then your problems would be messed up example if you have a+a it would be 2a make sense? so you want everything combined then you have to solve. theres no possible way of solving these without numbers number would have to be added although youll probably end up getting rid of the numbers in the end. after you combine like terms do the rest of solving


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7 0
3 years ago
What are two things an electric circuit needs to work?
steposvetlana [31]

Step-by-step explanation:

a power supply, a load suited to the power supply, and wiring as a conductor

7 0
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Read 2 more answers
The diameter of a particle of contamination (in micrometers) is modeled with the probability density function f(x)= 2/x^3 for x
natulia [17]

Answer:

a) 0.96

b) 0.016

c) 0.018

d) 0.982

e) x = 2

Step-by-step explanation:

We are given with the Probability density function f(x)= 2/x^3 where x > 1.

<em>Firstly we will calculate the general probability that of P(a < X < b) </em>

       P(a < X < b) =  \int_{a}^{b} \frac{2}{x^{3}} dx = 2\int_{a}^{b} x^{-3} dx

                            = 2[ \frac{x^{-3+1} }{-3+1}]^{b}_a   dx    { Because \int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a }

                            = 2[ \frac{x^{-2} }{-2}]^{b}_a = \frac{2}{-2} [ x^{-2} ]^{b}_a

                            = -1 [ b^{-2} - a^{-2}  ] = \frac{1}{a^{2} } - \frac{1}{b^{2} }

a) Now P(X < 5) = P(1 < X < 5)  {because x > 1 }

     Comparing with general probability we get,

     P(1 < X < 5) = \frac{1}{1^{2} } - \frac{1}{5^{2} } = 1 - \frac{1}{25} = 0.96 .

b) P(X > 8) = P(8 < X < ∞) = 1/8^{2} - 1/∞ = 1/64 - 0 = 0.016

c) P(6 < X < 10) = \frac{1}{6^{2} } - \frac{1}{10^{2} } = \frac{1}{36} - \frac{1}{100 } = 0.018 .

d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)

                                = (\frac{1}{1^{2} } - \frac{1}{6^{2} }) + (1/10^{2} - 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982

e) We have to find x such that P(X < x) = 0.75 ;

               ⇒  P(1 < X < x) = 0.75

               ⇒  \frac{1}{1^{2} } - \frac{1}{x^{2} } = 0.75

               ⇒  \frac{1} {x^{2} } = 1 - 0.75 = 0.25

               ⇒  x^{2} = \frac{1}{0.25}   ⇒ x^{2} = 4 ⇒ x = 2  

Therefore, value of x such that P(X < x) = 0.75 is 2.

8 0
3 years ago
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