We are given with an isosceles triangle having a vertex on the curve given y =<span>27-x^2</span> .
The area of the triangle, A= xy = x (27-x^2)
A' = 27-x^2-2x^2 = 0
x = 3
Amax = 3(27-9) = 54 units2
The value of x is 34.64 feet
<h3>Right-angled triangle</h3>
Find the diagram attached
- The height of the tent = 40 ft
- length of the rope = x
Get the value of x using the SOH CAH TOA identity

Hence the value of x is 34.64 feet
Learn more on SOH CAH TOA here: brainly.com/question/20734777
using the LCD method.... well, there are a couple of ways, but let's simply add them up.
well, the denominators are 5x and 2x... so the only LCD will just be 10x, since it's divisible by both, so let's use that one.

Answer:
12i
Step-by-step explanation:
be careful with your screenshots and make sure it doesnt show your name
8x + By + 92 = 0
(-4; 12) ⇒ x = -4; y = 12
subtitute
8 · (-4) + 12B + 92 = 0
-32 + 12B + 92 = 0
12B + 60 = 0 |subtract 60 from both sides
12B = -60 |divide both sides by 12
B = -5