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mixas84 [53]
3 years ago
8

Help with (18.) please, it's stupid idk it but please, any help is appreciated!

Mathematics
1 answer:
gayaneshka [121]3 years ago
6 0
60/(4/11) = (60×11)/4 = 165
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Answer this equation
Rudik [331]

Answer:

The solution to the box is

a = 2.1

b = 5.9

c = 0.9

d = 10

Step-by-step explanation:

To answer the equation, we simply name the boxes a,b,c and d.

Such that

a + b = 8 ---- (1)

b - c = 5 ------ (2)

d * c = 9 ------ (3)

a * d = 21 ------- (4)

Make d the subject of formula in (3)

d * c = 9 ---- Divide both sides by c

d * c/c = 9/c

d = 9/c

Substitute 9/c for d in (4)

a * d = 21

a * 9/c = 21

Multiply both sides by c

a * 9/c * c = 21 * c

a * 9 = 21 * c

9a = 21c ------ (5)

Make b the subject of formula in (1)

a + b = 8

b = 8 - a

Substitute 8 - a for b in (2)

b - c = 5

8 - a - c = 5

Collect like terms

-a - c = 5 - 8

-a - c = -3

Multiply both sides by -1

-1(-a - c) = -1 * -3

a + c = 3

Make a the subject of formula

a = 3 - c

Substitute 3 - c for a in (5)

9a = 21c becomes

9(3 - c) = 21c

Open bracket

27 - 9c = 21c

Collect like terms

27 = 21c + 9c

27 = 30c

Divide both sides by 30

27/30 = 30c/30

27/30 = c

0.9 = c

c = 0.9

Recall that a = 3 - c

So, a = 3 - 0.9

a = 2.1

From (1)

a + b = 8

2.1 + b = 8

b = 8 - 2.1

b = 5.9

From (3)

d * c = 9

Substitute 0.9 for c

d * 0.9 = 9

Divide both sides by 0.9

d * 0.9/0.9 = 9/0.9

d = 9/0.9

d = 10.

Hence, the solution to the box is

a = 2.1

b = 5.9

c = 0.9

d = 10

3 0
4 years ago
Use the graph of the exponential growth function f(x) = a(2x) to determine which statement is true. f(0) = 2 when a =1/2 . f(0)
Kryger [21]

Math symbols were invented for a reason. They help communicate your intent. Here, it looks like you may intend

... f(x) = a(2^x)


When x=0, this will have the value "a". When x=1, this will have the value a^2. The appropriate selection is

... f(0) = 3 when a = 3

3 0
4 years ago
Read 2 more answers
Please I really need help
Zanzabum

Answer:

Gold is LESS expensive than platinym because SLOPE of graph is LESS

SLOPE gives UNIT DOLLARS PER OUNCE.

Step-by-step explanation:

sorry im late

5 0
3 years ago
Give this problem a try and try to solve this​
tia_tia [17]

Answer:

No solution

Step-by-step explanation:

Given equation is,

\frac{x^{\frac{1}{2}}+x^{-\frac{1}{2}}}{1-x}+\frac{1-x^{-\frac{1}{2}}}{1+x^\frac{1}{2}}-\frac{(4+x)^\frac{1}{2}}{(1-x)^\frac{1}{2}}=0

\frac{x^{\frac{1}{2}}+x^{-\frac{1}{2}}}{1-x}+\frac{1-x^{-\frac{1}{2}}}{1+x^\frac{1}{2}}=\frac{(4+x)^\frac{1}{2}}{(1-x)^\frac{1}{2}}

\frac{(x+1)}{\sqrt{x}(1-x)}+\frac{(\sqrt{x}-1)}{\sqrt{x}(1+\sqrt{x})}=(\frac{4+x}{1-x})^{\frac{1}{2}}

\frac{(\sqrt{x}+1)(x+1)+(\sqrt{x}-1)(1-x)}{\sqrt{x}(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^{\frac{1}{2}}

\frac{x\sqrt{x}+x+\sqrt{x}+1+\sqrt{x}-1-x\sqrt{x}+x}{\sqrt{x}(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^\frac{1}{2}

\frac{2x+2\sqrt{x}}{\sqrt{x}(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^\frac{1}{2}

\frac{2(\sqrt{x}+1)}{(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^\frac{1}{2}

\frac{2}{1-x}=(\frac{4+x}{1-x})^\frac{1}{2}  if x ≠ ±1

(\frac{2}{1-x})^2=\frac{4+x}{1-x}  [Squaring on both the sides of the equation]

\frac{4}{(1-x)}=(4+x)

4 = (1 - x)(4 + x)

4 = 4 - 4x + x - x²

0 = -3x - x²

x² + 3x = 0

x(x + 3) = 0

x = 0, -3

But both the solutions x = 0 and x = -3 are extraneous solutions, given equation has no solution.

5 0
4 years ago
Read 2 more answers
I need with this!!!!!!
Elena-2011 [213]
I’m gonna go with C sorry if I’m wrong
8 0
3 years ago
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