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STatiana [176]
3 years ago
11

Factoring 28y^2+43y-48

Mathematics
2 answers:
Tcecarenko [31]3 years ago
8 0
28y^2+43y-48 \\ \\  28y^2 + 64y - 21y - 48 \ / \ factor \\ \\ 4y(7y + 16) - 3(7y + `16) \ / \ factor \ out \ common \ terms \\ \\ (7y + 16)(4y - 3) \ / \ factor \ out \ 7y + 16 \\ \\

So, your answer to this problem is (7y + 16)(4y - 3).
Tema [17]3 years ago
3 0
28y^2+ 43y -48
= 28x^2 +(-21x+ 64x) -48
= (28x^2 -21x)+ (64x -48)
= 7x* (4x -3)+ 16* (4x -3)
= (4x -3)(7x+ 16)

Final answer: (4x -3)(7x+ 16).
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Given

jacinta buys 4 pounds of turkey and 2 pounds of ham & pays a total of $30, turkey costs $1.50 less per pound than the ham.

find out the combined cost of 1 pound of turkey and 1 pound of ham

To proof

As given in the question

jacinta buys 4 pounds of turkey and 2 pounds of ham

total pay by jacinta = $30

let us assume that the price of the ham = x

as given in the question

turkey costs $1.50 less per pound than the ham

turkey costs becomes = x - 1.50

then the equation becomes

30 = 4 (x - 1.50) + 2x

30 = 4x + 2x - 6

36 = 6x

x = 6

thus

ham cost per pound = $6

turkey cost per pound = 6 - 1.50

                                    = $ 4.5

Now find out

cost of 1 pound of turkey + 1 pound of ham = $ 6 + $ 4.5

                                                                       = $ 10.5

Hence proved





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3 years ago
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Step-by-step explanation:

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