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Marta_Voda [28]
3 years ago
8

What is the supplementary angle to 69 degrees

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
4 0
The supplementary angle to 69 degrees would be 111 DEGREES.
because it has to add up to 180 (69 + 111 = 180)
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In the figure below, UX and UV are tangent to the circle centered at 0. The segment XV passes through the center of the
Karo-lina-s [1.5K]

Answer:

2.5

Step-by-step explanation:

The computation of the XW is shown below

As triangle UVX is a right angle

So

VU^2 = XU^2 - VX^2

VU^2 = 15.7^2 - 8.5^2

VU^2 = 246.49 - 72.25

VU^2 = 174.24

VU = 13.2

As VU = WX because of same point tangent

NOw XW is

= UX - UW

= 15.7 - 13.2

= 2.5

8 0
3 years ago
The ratio of the sides of 2 cubes is 2 to 7. If the volume of the smaller cube is 32 u3, then the volume of the larger cube is _
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\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&Sides&Area&Volume\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array} \\\\
-----------------------------\\\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\

\bf \cfrac{small}{large}\qquad \cfrac{s}{s}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\implies \cfrac{2}{7}=\cfrac{\sqrt[3]{32}}{\sqrt[3]{v}}\implies \cfrac{2}{7}=\sqrt[3]{\cfrac{32}{v}}\implies \left( \cfrac{2}{7} \right)^3=\cfrac{32}{v}
\\\\\\
\cfrac{2^3}{7^3}=\cfrac{32}{v}\implies v=\cfrac{7^3\cdot 32}{2^3}
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Help me with 26 ASAP <br> Please show work<br> Random Answers will be moderated! Thanks :)
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the time t required to drive a certain distance varies inversely with the speed, r. if it takes 4 hours to drive the distance at
valina [46]
Hello,

Answer A

d :the distance in miles
t: the time in hours
v: the speed in miles/hours (vistesse)


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In the right triangle shown, m<br> How long is YZ ?
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Can i see a picture of the triangle/ angle ?
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