Question

Consider this function.

Answer 1

Answer: A) $x=\frac{5}{2}$ and  $x=-\frac{2}{3}$

Step-by-step explanation:

Make the quadratic function $f(x)=6x^2-11x-10$ equal to zero:

$6x^2-11x-10=0$

Having the form $ax^2+bx+c=0$, the zeros can be calculated with a formula called "Quadratic formula":

$x=\frac{-b\±\sqrt{b^2-4ac}}{2a}$

Then:

Identify a, b and c:

$a=6\\b=-11\\c=-10$

Finally, substitute them into  the Quadratic formula:

$x=\frac{-(-11)\±\sqrt{(-11)^2-4(6)(-10)}}{2(6)}\\\\x=\frac{11\±\sqrt{361}}{12}\\\\x=-\frac{2}{3}\\\\x=\frac{5}{2}$

Answer 2

Answer:

2, 3, 5

Step-by-step explanation:

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