Answer:
go to a called math and way but without the space or the and
Step-by-step explanation:
Answer:
4 I believe
Step-by-step explanation:
sorry if im wrong, (didn't know if the and was to add or multiply,sorry!)
Answer:
yes
Step-by-step explanation:
Answer:
show how you know .. :D good rhyme
Step-by-step explanation:
park = 4" x 6" ( inches) small park
but one inch = 30 miles ooh big park
4*30 X 6*30
120 X 180 miles... like a big game range? :? very big
since we only have 6 square inches to fit the map into... then.. what size of map would fit? what size equals 6 inches? 2 x 3 ? hmm yes that's 6
soooo shrink the 4" x 6" to 2"x 3" so the scale needs to double or
1 inch = 60 miles
2"*60 x 3"*60 = 120 x 180 miles.. looks good try that :)
Answer:
10m x 15m
Step-by-step explanation:
You are given some information.
1. The area of the garden: A₁ = 150m²
2. The area of the path: A₂ = 186m²
3. The width of the path: 3m
If the garden has width w and length l, the area of the garden is:
(1) A₁ = l * w
The area of the path is given by:
(2) A₂ = 3l + 3l + 3w + 3w + 4*3*3 = 6l + 6w + 36
Multiplying (2) with l gives:
(3) A₂l = 6l² + 6lw + 36l
Replacing l*w in (3) with A₁ from (1):
(4) A₂l = 6l² + 6A₁ + 36l
Combining:
(5) 6l² + (36 - A₂)l +6A₁ = 0
Simplifying:
(6) l² - 25l + 150 = 0
This equation can be factored:
(7) (l - 10)*(l - 15) = 0
Solving for l we get 2 solutions:
l₁ = 10, l₂ = 15
Using (1) to find w:
w₁ = 15, w₂ = 10
The two solutions are equivalent. The garden has dimensions 10m and 15m.
