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Kitty [74]
3 years ago
13

Your speed while waterskiing is 22 miles per hour. How fast are you traveling in kilometers per hour? Round your answer to the m

earest hundredth
Mathematics
1 answer:
timurjin [86]3 years ago
8 0

Answer:

35.41 km/h

Step-by-step explanation:

-Given the speed is 22 mph

-The kilometer equivalent of 1 mile is 1.60934 kilometers -hence 22 kilometers will be 22*1.60934=35.40548 rounded off a 35.41 km. Since miles was per hour and km is per hour then speed is 35.41 km/h

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A radio telescope array is in an unpopulated desert region. The array covers a rectangular area that is one fourth square kilome
kramer

Answer:

  3 km

Step-by-step explanation:

The area of a rectangle is given by the formula ...

  A = LW

Filling in the given information, we can solve for the length.

  1/4 = L·(1/12)

Multiplying by 12, we see that ...

  3 = L

The array is 3 kilometers long.

3 0
3 years ago
Joseph claims that a scatterplot in which the y-values increase as the x-values increase must have a linear association. Amy cla
quester [9]

Answer:

Amy is correct because a nonlinear association could increase along the whole data set, while being steeper in some parts than others. The scatterplot could be linear or nonlinear.

Step-by-step explanation:

I just took the quiz, I hope this helps :).

7 0
2 years ago
Read 2 more answers
Finding the perimeter of each rectangle 96ft width 124ft length
dezoksy [38]

Answer:

440 ft

Step-by-step explanation:

Perimeter(p) of a rectangle is 2l + 2w

Where 'l' is the length and 'w' is the width.

p = 2(96ft) + 2(124ft) = 192 ft + 248 ft = 440 ft

5 0
2 years ago
The authors of a paper describe an experiment to evaluate the effect of using a cell phone on reaction time. Subjects were asked
Serggg [28]

Answer:

a) The 99% confidence interval would be given by (24.409;24.979)  

b) n=464

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Part a

The confidence interval for the mean is given by the following formula:  

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:  

df=n-1=47-1=46  

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,46)".And we see that t_{\alpha/2}=2.01  

Now we have everything in order to replace into formula (1):  

525-2.01\frac{75}{\sqrt{47}}=503.01  

525+2.01\frac{75}{\sqrt{47}}=546.99  

So on this case the 95% confidence interval would be given by (503.01;546.99)

Part b

The margin of error is given by this formula:  

ME=t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

And on this case we have that ME =7 msec, we are interested in order to find the value of n, if we solve n from equation (1) we got:  

n=(\frac{t_{\alpha/2} s}{ME})^2 (2)  

The critical value for 95% of confidence interval is provided, t_{\alpha/2}=2.01 from part a, replacing into formula (2) we got:  

n=(\frac{2.01(75)}{7})^2 =463.79 \approx 464  

So the answer for this case would be n=464 rounded up to the nearest integer  

8 0
3 years ago
A student has received the following test scores: 71%, 89%, 72%,
lidiya [134]

Answer: 81%

Step-by-step explanation:

From the question, we are informed that a student received the following test scores: 71%, 89%, 72%,

84% and 83% in 5 tests and the student wants to maintain an average of 80%.

The lowest score/grade they can receive on the next test to maintain at least an 80% average first thus:

First, to make it easy we can remove the percent sign. Then we multiply 80 by 6 since we're calculating for 6 tests scores. This will be:

= 80 × 6

= 480

We then add all the 5 test scores. This will be:

= 71 + 89 + 72 + 84 + 83

= 399

We then subtract the values gotten. This will be:

= 480 - 399

= 81

This means the student must get at least 81%

5 0
3 years ago
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