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vaieri [72.5K]
4 years ago
11

Please help me with my math problem!!Thank you!! :)

Mathematics
1 answer:
vova2212 [387]4 years ago
6 0

Check the picture below.

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Can someone PLEASE help me with this question?
disa [49]

9514 1404 393

Answer:

  11

Step-by-step explanation:

The future value of the account is given by the formula ...

  A = P(1 +r/12)^(12t) . . . . principal P invested at rate r for t years

Solving for t, we find ...

  A/P = (1 +r/12)^(12t) . . . . . . . . . . . divide by P

  log(A/P) = 12t·log(1 +r/12) . . . . . . take logs

Divide by the coefficient of t, then fill in the numbers.

  t = log(A/P)/(12·log(1 +r/12)) = log(202800/93000)/(12·log(1 +.068/12))

  t ≈ 11.497

It will take about 11 years for the account balance to reach the desired amount.

4 0
3 years ago
Find out the number of combinations and the number of permutations for 8 objects taken 6 at a time. Express your answer in exact
umka2103 [35]

Solution:

The permutation formula is expressed as

\begin{gathered} P^n_r=\frac{n!}{(n-r)!} \\  \end{gathered}

The combination formula is expressed as

\begin{gathered} C^n_r=\frac{n!}{(n-r)!r!} \\  \\  \end{gathered}

where

\begin{gathered} n\Rightarrow total\text{ number of objects} \\ r\Rightarrow number\text{ of object selected} \end{gathered}

Given that 6 objects are taken at a time from 8, this implies that

\begin{gathered} n=8 \\ r=6 \end{gathered}

Thus,

Number of permuations:

\begin{gathered} P^8_6=\frac{8!}{(8-6)!} \\ =\frac{8!}{2!}=\frac{8\times7\times6\times5\times4\times3\times2!}{2!} \\ 2!\text{ cancel out, thus we have} \\ \begin{equation*} 8\times7\times6\times5\times4\times3 \end{equation*} \\ \Rightarrow P_6^8=20160 \end{gathered}

Number of combinations:

\begin{gathered} C^8_6=\frac{8!}{(8-6)!6!} \\ =\frac{8!}{2!\times6!}=\frac{8\times7\times6!}{6!\times2\times1} \\ 6!\text{ cancel out, thus we have} \\ \frac{8\times7}{2} \\ \Rightarrow C_6^8=28 \end{gathered}

Hence, there are 28 combinations and 20160 permutations.

7 0
1 year ago
Diagnostic Test
Semmy [17]

Answer:

B.

Step-by-step explanation:

5 0
3 years ago
Really NEED help PLEASE EXPLAIN!!
Leviafan [203]

Answer:

Lines y = -x+4 and y= 3x+3 intersect the y-axis

5 0
3 years ago
There are two numbers such that , if both of them are individually increased by 5 and then by the same percentage as they were i
QveST [7]
Let the two numbers be x and y.
Let m =  the fraction (or percentage) for increasing the numbers.
 
Increase x by 5, multiply (x+5) by (1+m), and set it qual to 36.
(x + 5)*(1 + m) = 36

Increase y by 5, multiply (y+5) by (1+m), and set it equal to 36.
(y+5)*(1+m) = 36

Therefore
(x+5)*(1+m) = (y+5)*(1+m)
x + 5 = y + 5
x = y
x - y = 0

Answer: 0.
The difference between the two numbers is zero.
5 0
4 years ago
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